- #1
juantheron
- 247
- 1
Calculation of real values of $x$ in $\sqrt{4^x-6^x+9^x}+\sqrt{9^x-3^x+1}+\sqrt{4^x-2^x+1} = 2^x+3^x+1$
My Try:: Let $2^x = a$ and $3^x = b$ , Then
$\sqrt{a^2-a\cdot b+b^2}+\sqrt{b^2-b+1}+\sqrt{a^2-a+1} = a+b+1$
Now I am struck after that
Help required
Thanks
My Try:: Let $2^x = a$ and $3^x = b$ , Then
$\sqrt{a^2-a\cdot b+b^2}+\sqrt{b^2-b+1}+\sqrt{a^2-a+1} = a+b+1$
Now I am struck after that
Help required
Thanks