- #1
SMKJ
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- TL;DR Summary
- I need help calculating the RPM needed to launch a cricket ball from a ball launcher driven by a flywheel.
Assume the top image to be the simple version of the wheel configuration and the lower one to be the proposed way of wheel arrangement. In the newer version i want to use a heavy metal plate of approx 200gms and a wheel of 50gm instead of a heavy 200gm wheels due to sourcing issues.
This is what the metal plate looks like. The metal plate is about 100mm in diameter and the wheel is 114mm in diameter. My calculations are as follows:
wt_metal = 200gm = 0.2kg
wt_wheel = 50gm = 0.05kg
desired exit velocity of ball = v = 70kmph = approx 20m/s
wt_ball = 70gm = 0.07kg
Assume that the wheel and the metal plate is just a disk so as to ease calculations:
Moment of Inertia of wheel = 1/2 m_wheel r^2
Moment of inertia of metal plate = 1/2 m_plate r^2
Total moment of inertia = 3.31E-4 kgm^2 = I
Applying Energy conservation:
1/2 m_ball v_ball^2 = 1/2 I w^2
w^2/V_ball^2 = m_ball/I = 211.3
w/v_ball = 14.53
v_ball being 20 m/s
w = 290 rad/s
converting this to RPM = approx 3000 RPM
Driving this setup with 5010, 750Kv motors at 16V i expect a driving RPM range of 0 - 12000
Can someone please validate/correct my theories!!!
Solidworks files for the motor to wheel adapter and the 2 designs of the metal plate are attached:
https://drive.google.com/drive/folders/1XR9uy64MSJkxj9szRVHWCp2k7mFUlYS2?usp=sharing