Filip Larsen said:Two things you need to include in your calculation:
1) at 3600 km above the surface of Earth, the acceleration due to gravity is not same as at the surface.
2) The radius in the circular motion equation is not 3600 km.
The correct value is a bit more than what you got.
To calculate the velocity of a satellite at a given altitude above Earth, you can use the formula: V = √(GM/R), where V is the velocity, G is the gravitational constant, M is the mass of Earth, and R is the distance between the satellite and the center of Earth. In this case, R would be 3600 km (or 3,600,000 meters).
The average velocity of a satellite at 3600 km above Earth will vary depending on its orbital path and the specific location of the satellite at any given time. However, using the formula mentioned above, the average velocity can be calculated to be approximately 7.5 km/s.
The speed of sound is approximately 343 m/s, while the velocity of a satellite at 3600 km above Earth is about 7.5 km/s. This means that a satellite is traveling at a much higher velocity than the speed of sound.
Yes, the velocity of a satellite at 3600 km above Earth can change over time due to factors such as changes in its orbital path, atmospheric drag, and gravitational pull from other celestial bodies. However, these changes are typically not significant and the satellite will maintain a relatively constant average velocity.
Calculating the velocity of a satellite at a specific altitude above Earth is important for understanding its orbital path and predicting its movements. It is also crucial for maintaining the satellite's stability and ensuring it stays in its designated orbit. Additionally, knowing the velocity can help with planning and coordinating communication and data transmission with the satellite.