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PRASHANT KUMAR said:while solving the problem if we do such type of substitution then it is necessary to put a negative sign otherwise it will be wrong?
No. But, you were going to use:
(X) ##\int_{-1}^{1}\delta(x)dx = 1##
And, you were going to assume that the order of the limits doesn't matter. So, you were going to assume that:
##\int_1^{-1}\delta(x)dx = 1##
Which would be wrong. So, you have to get the limits in the right order before you apply equation (X).
Take a look at the first property of the definite integral here (half way down the page).
http://tutorial.math.lamar.edu/Classes/CalcI/DefnOfDefiniteIntegral.aspx