- #1
Jim Ruxton
I want to know how much electrical power I could potentially generate by putting a generator at the pivot point of a rotating arm. I figured I can calculate the Kinetic Energy of the arm by:
E=(Iw**2)/2 where I is moment of Inertia and w is angular velocity.
I = (mL**2)/3 for a uniform rod
in my case I am using L=.25 metre , m= .09 Kg and w =2Pi rad/sec
This gives me approx. .04 J . Assuming this is rotating at a constant velocity how do I know what the instantaneous output power of the generator could be assuming 100% efficiency. I know Power is just Energy/Time but what do I use for time in this case? I am used to calculating electrical power as voltage*amps but never figured out how to convert from the mechanical equivalent. Ultimately I want to figure out if I can power an LED using a small generator. Thanks
E=(Iw**2)/2 where I is moment of Inertia and w is angular velocity.
I = (mL**2)/3 for a uniform rod
in my case I am using L=.25 metre , m= .09 Kg and w =2Pi rad/sec
This gives me approx. .04 J . Assuming this is rotating at a constant velocity how do I know what the instantaneous output power of the generator could be assuming 100% efficiency. I know Power is just Energy/Time but what do I use for time in this case? I am used to calculating electrical power as voltage*amps but never figured out how to convert from the mechanical equivalent. Ultimately I want to figure out if I can power an LED using a small generator. Thanks