Calculate the pressure of the following mixture.

In summary, the oil reservoir discussed has a water/oil contact (WOC) at 12000ft with a water column at 800ft, oil at 500ft, and gas at 600ft. Using the given equations and densities, the pressure at WOC is calculated to be 64.7 Mpa. The pressure at 12500ft is 34.7 Mpa. Other calculations for pressures at 11700ft and 11000ft are not provided.
  • #1
marcoskids
14
0

Homework Statement



An oil reservoir contains at water/oil contact (WOC) of 12000ft contains a water column at 800ft, oil at 500ft and gas at 600ft height

Calculate the pressure at WOC, 12500, 11700 and 11000 ft?

Homework Equations



P = rho g h + Patm

1 ft = 0.305m
Rho water = 1000
Rho Oil = 800
Rho gas = 120

The Attempt at a Solution



P WOC = 1000*9.81*(12000*0.305) + 800*9.81*(12000*0.305)+patm = 64.7Mpa

For the water column for example would the pressure be:

Pwoc + (1000*9.81*(800*0.305) = 67.1Mpa ?
or
Pwoc + (1000*9.81*((12000-800)*0.305)) = 98.2Mpa
or
Pwoc+(1000*9.81*((12000+800)*0.305)) = 102.3Mpa

Basically what height do I have to use?

And what densitys do I need to use for the depths at 12000, 11700 and 11000ft please?
 
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  • #2
New approach does this look better?

Pwoc = (rhoWgh ) + (rhoOgh)
= (1000*9.8*(12000*0.305)) + (800*9.8*(12000*0.305)
= 64.6 Mpa

Pgoc = (rhoG gh) + (rhoO gh)
= ((120*9.8*((12000-800)*0.305))) + (800*9.8*((12000-800)*0.305)))
= 30.8 Mpa

P12500 = (rhoW gh)
= 1000*9.8*(12500*0.305)
= 34.7 Mpa
 

FAQ: Calculate the pressure of the following mixture.

What is pressure and how is it calculated?

Pressure is defined as the force per unit area exerted by a gas or liquid. It can be calculated by dividing the force by the area over which the force is applied. The SI unit for pressure is pascal (Pa).

What is the ideal gas law and how is it used to calculate pressure?

The ideal gas law, also known as the universal gas law, describes the relationship between pressure, volume, temperature, and number of moles of a gas. It is represented by the equation PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is the temperature. By rearranging the equation, we can calculate pressure by dividing the product of number of moles, gas constant, and temperature by the volume.

How do you calculate the pressure of a mixture of gases?

To calculate the pressure of a mixture of gases, we use Dalton's law of partial pressures. This law states that the total pressure of a mixture of ideal gases is equal to the sum of the partial pressures of each individual gas. The partial pressure of each gas can be calculated using the ideal gas law, and then added together to find the total pressure of the mixture.

What factors can affect the pressure of a gas mixture?

The pressure of a gas mixture can be affected by several factors, including temperature, volume, and the number of moles of gas present. Additionally, the types of gases present in the mixture and their respective partial pressures can also impact the overall pressure.

Can the pressure of a gas mixture be negative?

No, the pressure of a gas mixture cannot be negative. Pressure is a measure of the force exerted by the gas molecules, and a negative pressure would indicate a force pulling the gas molecules apart, which is physically impossible. Therefore, the pressure of a gas mixture will always be positive.

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