Calculate the R-value of the stack of materials

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In summary, the R-value of the stack of materials is equal to the sum of the R-values of each individual material, which can be calculated by dividing the thickness of the material by its thermal conductivity. The heat flow per unit area through the stack can be found by using the formula Q/A = kΔT/d, where Q/A represents heat flux, k is thermal conductivity, ΔT is temperature difference, and d is the thickness of the material.
  • #1
ninaw21
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Homework Statement



Calculate the R-value of the stack of materials whose total thickness is made up of the
individual thicknesses:
material 1; k = 0.123 W/m/K, thickness = 0.103 m
material 2: k = 0.234 W/m/K, thickness = 0.092 m
material 3: k = 0.345 W/m/K, thickness = 0.081 mHence calculate the heat flow per unit area through such a stack with has temperatures of
20 °C and -5 °C on opposite sides of the stack

Homework Equations



R = ΔT/QA, Where QAis heat flux

The Attempt at a Solution


I've no idea how to do this problem! Please help!
 
Last edited:
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  • #2
Welcome to PF, ninaw21! :smile:

In equilibrium the heat flow through material 1 must be equal to the flow through material 2, which in turn must be equal to the flow in material 3.

If you introduce 2 variables representing the temperature between materials 1 and 2, respectively materials 2 and 3, you can set up a system of equations that you can solve.

Do you know how to do that?
 
  • #3
Thank you! I know that they're equal but I don't know the variables to use..
 
  • #4
Well, what can you come up with?
Which symbols can you think of?
 
  • #5
q = specific heat x m x Δt,

where q is heat flow, m is mass in grams, and Δt is the temperature change. ??
 
  • #6
Hmm, that is the formula that relates absorbed heat to change in temperature.
I'm afraid that is not the formula to use here.

Do you have a formula that relates the R-value to the thermal conductivity k?

Actually, to find the R-value of the stack, you can simply add the R-values of the 3 materials.
 
  • #7
Is this the formula that is used then :

deltaQ/deltat = kAdeltaT/d, where: deltaQ = heat flow, deltat = time, k = thermal conductivity, deltaT = temp, and d = distance ??
(Thanks for all the help!)
 
  • #8
That's closer.

So you have:
$$R = {\Delta T \over {dQ \over dt} / A}$$
and
$${dQ \over dt} = {k A \Delta T \over d}$$
where d is distance the heat travels, or in other words, the thickness of the material,
and where A is the surface of the material.

Note that the heat flux ##Q_A## that you had in your opening post, is actually the heat flow per unit area and per unit of time.Can you deduce what the R-value will be of each material?
 
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  • #9
I'll make it simpler.
The relation between R and k is: ##R = {d \over k}##.
 
  • #10
Thank you so much! :)
 
  • #11
So... do you have your answer now?
 
  • #12
Yes! :)
 
  • #13
Good! :smile:
 

FAQ: Calculate the R-value of the stack of materials

What is the R-value of a stack of materials?

The R-value of a stack of materials is a measure of its thermal resistance, or how well it can resist the flow of heat. It is typically expressed in units of square meters Kelvin per watt (m²K/W).

How is the R-value of a stack of materials calculated?

The R-value of a stack of materials is calculated by dividing the thickness of the stack by the thermal conductivity of each material in the stack, and then adding up the individual R-values of each layer. This calculation takes into account the number of layers and their respective thicknesses and thermal conductivities.

What factors affect the R-value of a stack of materials?

The R-value of a stack of materials is affected by a number of factors, including the type and thickness of each material, the number of layers in the stack, and the presence of any air gaps or insulation materials. The R-value may also change over time due to factors such as settling or moisture accumulation.

How does the R-value of a stack of materials impact energy efficiency?

The higher the R-value of a stack of materials, the more effectively it can resist the flow of heat. This means that buildings with higher R-values in their walls, floors, and roofs will require less energy to maintain a comfortable internal temperature, resulting in lower energy bills and a smaller carbon footprint.

Can the R-value of a stack of materials be improved?

Yes, the R-value of a stack of materials can be improved by using materials with higher thermal resistances, increasing the thickness of the stack, and minimizing air gaps and thermal bridging. The use of insulation materials, such as foam or fiberglass, can also significantly improve the R-value of a stack of materials.

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