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rhiannynd
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In a simple series circuit there is a 12V supply battery, 12μ6 F capacitor, a Resistor, and a 2v drop LED with an imax of 30mA. frequency is 10Hz
Calculate the resistance of the resistor so that the LED just stays on.
Resistance of Capacitor Xc = 1/2∏fC
P=VI
V=IR
Impedence = √R^2+Xc^2
Xc = 1/2∏x10x12x10^6
=1326.3 Ω
P=vxI
P = 12 x 0.03A
=0.36w
i have no idea what else to do ! any help would be greatly appreciated please please please
Calculate the resistance of the resistor so that the LED just stays on.
Homework Equations
Resistance of Capacitor Xc = 1/2∏fC
P=VI
V=IR
Impedence = √R^2+Xc^2
The Attempt at a Solution
Xc = 1/2∏x10x12x10^6
=1326.3 Ω
P=vxI
P = 12 x 0.03A
=0.36w
i have no idea what else to do ! any help would be greatly appreciated please please please