- #1
JustAStudent
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Homework Statement
Q1<------>Q2<------>Q3
In the above figure, the distance between Q1 and Q2 is equal to the distance between Q2 and Q3. That distance is R=1.5 m.
Q1= 2.24x10-6 C, Q2=+Q1 and Q3=-Q1.
Calculate the total force on Q1. Give your answer with a positive number for a force directed to the right, or a negative number for a force directed to the left.
Homework Equations
|F|=((k)(Q1)(Q2))/r^2
The Attempt at a Solution
|F13|=((k)(2.24E-6)(2.24E-6))/(1.5+1.5)^2
=0.0050176
Because Q1=positive and Q3=negative there is an attraction and therefore the value should be negative (to the left)
SO, =-0.0050176
|F12| =((k)(2.24E-6)(2.24E-6))/(1.5)^2
=0.0200704
Because Q1=positive and Q2=positive, there is a repulsion and therefor the value should be positive (to the right)
SO: 0.0200704
Add them together to get the net force: -0.0050176 +0.0200704=0.0150528
I have no idea what I am doing wrong