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rem45
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I agree that a nonrelativistic approach should be fine - it is a very good approximation.mathman said:Since the neutron rest mass is approximately 940 Mev, you probably could use E=(mv^2)/2 to get v. (v=c/22?).
The velocity of a 1MeV neutron can be calculated using the formula v = √(2E/m), where E is the energy of the neutron in MeV and m is the mass of the neutron in MeV/c^2.
The mass of a neutron is approximately 939.57 MeV/c^2, which is equivalent to 1.67493 x 10^-27 kilograms.
No, according to the theory of relativity, the speed of light is the maximum speed attainable by any particle with mass. Therefore, the velocity of a 1MeV neutron cannot be greater than the speed of light.
The velocity of a 1MeV neutron can be measured using various methods such as time-of-flight measurements, neutron spectroscopy, or by using specialized detectors such as a scintillation detector or a bubble chamber.
Calculating the velocity of a 1MeV neutron is important in various fields such as nuclear physics, astrophysics, and medical imaging. It helps in understanding the behavior of neutrons in different environments and in developing technologies that utilize neutron interactions.