Calculate voltage over capacitor and resistance

In summary, calculating voltage across a capacitor and resistor involves using the formulas derived from Ohm's Law and the principles of capacitive charging and discharging. The voltage across a capacitor can be determined using the formula V = Q/C, where V is voltage, Q is charge, and C is capacitance. For a resistor in a circuit, the voltage can be calculated using V = IR, with I being the current and R the resistance. In circuits with both components, Kirchhoff's laws may be applied to analyze the voltage distribution and relationships.
  • #1
Sailhill
3
2
Homework Statement
The task is to calculate the voltage over a capacitor and resistance after 1.0 ms. (Ux) if the capacitor had no charge before the switch was closed.
Relevant Equations
Vs=Vc*(1-exp((-t)/(R*C)))
Hi! I tried by using the Thevenin. Later using Vth and Rth to calculate Vs(0.1ms).
After that I divided the voltage from E over R1 and R3.

The circuit and my attempt:
 
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  • #2
Is there a question you wish to ask? The numbers you put down are useless without units attached to them.
 
  • #3
1) What is your question?
2) Check your value for Vth. I found something different. If you think you were correct, please describe your method.
3) Your result for the exponential calculation used 1msec, but your notes say 10msec.
4) Personally, I very much prefer to use a scientific or engineering notation, like 1⋅10-6 instead of 0.000001. I HATE counting long strings of zeros; I often screw it up and have little confidence in my accuracy.

In general it looks to me like you need to slow down a bit and don't skip steps. It just seems a bit sloppy to me.
 
  • #4
DaveE said:
I HATE counting long strings of zeros;
Amen, brother. In this particular problem time ##t## is given in ms so it would be expedient to convert the time constant to ms before substituting. That is one of the many reasons why putting down units is important.
 
  • #5
DaveE said:
1) What is your question?
2) Check your value for Vth. I found something different. If you think you were correct, please describe your method.
3) Your result for the exponential calculation used 1msec, but your notes say 10msec.
4) Personally, I very much prefer to use a scientific or engineering notation, like 1⋅10-6 instead of 0.000001. I HATE counting long strings of zeros; I often screw it up and have little confidence in my accuracy.

In general it looks to me like you need to slow down a bit and don't skip steps. It just seems a bit sloppy to me.
1) The question in the task is: "What is the voltage across capacitor Ux 1ms after the switch "S" is closed?"
The capacitor is initially uncharged. I'm having difficulty obtaining the correct answer and identifying my mistake.
2) I recalculated and now obtained the Thevenin voltage (Vth) as 1.1905 V.
3) Ah, that was an error. The time should indeed be 1 ms.
4) Sorry for the messy notes. I re did the calculation, trying to keep it clearer.

I believe I've correctly determined the Thevenin equivalent now. However, my main challenge lies in calculating Vc and integrating it with Vs. I'm uncertain about the accuracy of my method in calculating Vs and Vc separately and then combining them. I wrote in the notes from what part I am uncertain.
 

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  • #6
I agree with your answer that the voltage across the capacitor and resistor R2 at t = 1 ms is 0.87 V. Isn't that what you had to find? I don't understand what you mean by (Ux). If this problem is originally in a non-English language, try https://translate.google.com/ and post the translation it gives you.
 
  • #7
Sailhill said:
However, my main challenge lies in calculating Vc and integrating it with Vs.
Are you asking how the exponential response formula ##V_c = V_s (1-e^{ \frac{-t}{\tau}}) ## is derived?
If so, have you studied calculus and simple differential equations yet?

You will need to solve for the currents, mostly through R1. Then use KVL to determine the voltage Ux.
 
  • #8
Thanks for the help! I used KVL and got the correct answer, much appreciated :smile:

Vs - (R1*I) - Vc - (R3*I)=0
I=1.29 mA
VR3=I * R3
VR3=1.29 mA * 2.2k Ohm, (VR3: voltage over R3)
Ux=VR3 + Vc
Ux=3.71 V
 
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Likes BvU and DaveE

FAQ: Calculate voltage over capacitor and resistance

How do you calculate the voltage across a capacitor in an RC circuit?

The voltage across a capacitor in an RC circuit can be calculated using the formula \( V_C(t) = V_0 \cdot e^{-\frac{t}{RC}} \) for a discharging capacitor, where \( V_0 \) is the initial voltage, \( R \) is the resistance, \( C \) is the capacitance, and \( t \) is the time. For a charging capacitor, the formula is \( V_C(t) = V_s \cdot (1 - e^{-\frac{t}{RC}}) \), where \( V_s \) is the supply voltage.

What is the time constant in an RC circuit?

The time constant in an RC circuit, denoted by the Greek letter tau (τ), is the product of the resistance (R) and the capacitance (C). It is given by the formula \( \tau = RC \). The time constant represents the time it takes for the voltage across the capacitor to either charge or discharge to approximately 63% of its final value.

How do you calculate the voltage across the resistor in an RC circuit?

The voltage across the resistor in an RC circuit can be calculated using Ohm's Law, \( V_R(t) = I(t) \cdot R \), where \( I(t) \) is the current at time \( t \). For a charging capacitor, the current is \( I(t) = \frac{V_s}{R} \cdot e^{-\frac{t}{RC}} \), and for a discharging capacitor, it is \( I(t) = \frac{V_0}{R} \cdot e^{-\frac{t}{RC}} \). Therefore, the voltage across the resistor is \( V_R(t) = V_s \cdot e^{-\frac{t}{RC}} \) for charging and \( V_R(t) = V_0 \cdot e^{-\frac{t}{RC}} \) for discharging.

What happens to the voltage across the capacitor and resistor over time in an RC circuit?

In an RC circuit, as time progresses, the voltage across the capacitor increases exponentially towards the supply voltage \( V_s \) if it is charging, or decreases exponentially to zero if it is discharging. Conversely, the voltage across the resistor decreases exponentially to zero if the capacitor is charging, or increases to the supply voltage and then decreases to zero if it is discharging.

How do you determine the initial voltage across a capacitor in an RC circuit?

The initial voltage across a capacitor in an RC circuit depends on the initial conditions of the

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