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mutzy188
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Homework Statement
How much weight would 5g of CuSO4 5H2O lose if ti were dried at 120 degrees C for 12 hours (i.e. if it were heated to drive off all the water of hydration)?
The Attempt at a Solution
CuSO4 = 159.61 g/mol
H2O = 18 g/mol = 90 g for 5 mols
159.61/(159.61 + 90) = 6.25%
5 g * 6.25% = amount of CuSO4 = .313 g
5 - .313 = how much H2O lost = 4.687 g
but this isn't the correct answer.
Any help would be greatly appreciated
Thanks