- #1
rowdy3
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Human body temperatures are normally distributed with a mean of 98.20 and a standard deviation of 0.62.
Find the z-score corresponding to a body temperature of 97.93.
This is what I did.
97.93 - 98.20 / .62
I got -.44.
WOuld a temperature of 99.71 be considered unusual?
99.71 - 98.20 / .62.
My answer 2.44. Yes because it's more than 2 SD.
Find the z-score corresponding to a body temperature of 97.93.
This is what I did.
97.93 - 98.20 / .62
I got -.44.
WOuld a temperature of 99.71 be considered unusual?
99.71 - 98.20 / .62.
My answer 2.44. Yes because it's more than 2 SD.