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JDiorio
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Homework Statement
A patient with thyroid problems has radioactive iodine 123 deposited in his thyroid gland. If the iodine has an initial activity of 2.5 MBq, what is its activity after 24 days?
Homework Equations
A(t)= Ao e^ -(ln(2)/half-life)*t
The Attempt at a Solution
not sure what i did wrong here.. hope its not another calculating error.. but i found the half life of iodine 123 is 13.1 hours or .5458 days. So i have that ln(2)/.5458 times 24 = 30.48.
Then e^-30.48=5.795E-14.. i just multiply this number by 2.5E6 and get 1.45E-7 Bq.. not sure what I am doing wrong