- #1
Felicity Wang
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Homework Statement
The white ball in the figure has a speed of 1.81 m/s and the yellow ball is at rest prior to an elastic glancing collision. After the collision the white ball has a speed of 1.37 m/s. To the nearest tenth of a degree, measured counterclockwise from east, what angle does it scatter at if the yellow ball is scattered at 280degrees?
Homework Equations
mv1=mv1'sin(@)+mv2'sin(@)
The Attempt at a Solution
(2kg x 1.81m/s) = (2kg x 1.37) sin(@) +(1kg) v2' sin(280)
v2':
1/2mv1^2 = 1/2mv1'^2 + 1/2mv2'^2
v2'= 1.67m/s
The answer is 37 degrees but I am not sure how to progress from here.