- #1
ninjagowoowoo
- 75
- 0
M, a solid cylinder (M=1.39 kg, R=0.137 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.710 kg mass, i.e., F = 6.965 N. Calculate the angular acceleration of the cylinder.
That I can do... But then I get...
If instead of the force F an actual mass m = 0.710 kg is hung from the string, find the angular acceleration of the cylinder.
Why would the second situation be different than the first? And could you point me in the right direction? Thanks.
That I can do... But then I get...
If instead of the force F an actual mass m = 0.710 kg is hung from the string, find the angular acceleration of the cylinder.
Why would the second situation be different than the first? And could you point me in the right direction? Thanks.