Calculating Average Force in a Car Collision

In summary, a 1200 kg car driving into a brick wall and rebounding at different speeds has an average force of 204,000 Newtons acting on it during the collision.
  • #1
ScullyX51
36
0

Homework Statement


A 1200 kg car drives headlong into a brick wall at 14 m/s and rebound at 3 m/s. The collision lasts for .10 seconds. What is the average force on the car during the collision?


Homework Equations


F=ma
f*change in time= mass * change in velocity
f= mass*change in velocity / change in time


The Attempt at a Solution


I got the change in velocity to be 17 m/s. I did 14 m/s - (-3m/s) = 17 (I put the 3 as negative since it it rebounding it is going in the negative x direction.
f= 1200(17)/ .1 = 204,000. this is wrong..where am I messing up?
 
Physics news on Phys.org
  • #2
ScullyX51 said:

Homework Statement


A 1200 kg car drives headlong into a brick wall at 14 m/s and rebound at 3 m/s. The collision lasts for .10 seconds. What is the average force on the car during the collision?


Homework Equations


F=ma
f*change in time= mass * change in velocity
f= mass*change in velocity / change in time


The Attempt at a Solution


I got the change in velocity to be 17 m/s. I did 14 m/s - (-3m/s) = 17 (I put the 3 as negative since it it rebounding it is going in the negative x direction.
f= 1200(17)/ .1 = 204,000. this is wrong..where am I messing up?
The change in velocity is (final v - initial v). You may have a signage error. And don't forget the force unit.
 
  • #3
Looks good to me, except for you not including the correct unit for force.
 

FAQ: Calculating Average Force in a Car Collision

What does the term "average force" mean in science?

The term "average force" refers to the magnitude and direction of the total force acting on an object over a period of time. It is calculated by dividing the total amount of force by the duration of time in which the force was applied.

How is the average force calculated?

The average force can be calculated by dividing the change in an object's momentum by the duration of time in which the force was applied, using the formula F = Δp/Δt. It can also be calculated by dividing the total amount of force by the duration of time in which the force was applied, using the formula F = mΔv/Δt.

What is the difference between average force and instantaneous force?

The average force is the overall force acting on an object over a period of time, while the instantaneous force is the force acting on an object at a specific moment in time. The average force takes into account the duration of time in which the force was applied, whereas the instantaneous force does not.

Why is average force important in physics?

Average force is important in physics because it helps us understand the overall effect of a force on an object. By calculating the average force, we can determine the change in an object's momentum and predict its future motion. Average force is also used in many equations and laws, such as Newton's second law of motion.

Can the average force acting on an object ever be zero?

Yes, the average force acting on an object can be zero. This means that the overall force acting on the object over a period of time is balanced, resulting in no change in the object's momentum. For example, if a person pushes a box with a constant force in one direction, and another person pushes the same box with an equal force in the opposite direction, the average force would be zero.

Similar threads

Replies
9
Views
343
Replies
23
Views
2K
Replies
2
Views
2K
Replies
10
Views
3K
Replies
5
Views
5K
Replies
22
Views
2K
Back
Top