Calculating Ball Diameter in a Beaker: Accounting for Tension and Buoyancy

In summary: So we can say that the buoyant force is equal to the tension + mg. Then we can solve for the volume of the ball using the given density of water and the mass of the displaced water. Plugging in the volume value into the volume equation and solving for diameter, we get a diameter of about 4.6 cm. In summary, the diameter of the Ping-Pong ball is approximately 4.6 cm when submerged in water with a tension of 6.75 mN on the attached thread.
  • #1
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Ball in a Beaker - Diameter - Please Help!

Homework Statement



A thread attaches a 2.73-g Ping-Pong ball to the bottom of a beaker. When the beaker is filled with water so that the ball is totally submerged, the tension in the thread is 6.75 mN. Determine the diameter of the ball.

Homework Equations



r = [6(T + mg)/π × 10^3g]^1/3

The Attempt at a Solution



I am using the above equation but cannot get the right answer!
 
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  • #2


The equation is not correct. Try to derive the formula for the diameter yourself.

ehild
 
  • #3


ehild is correct, you need to derive the equation yourself. I would recommend thinking about the force diagram first. Which forces are pulling the ping pong ball down? Which forces are pulling it up? They have to be equal and opposite to each other if the ball isn't accellerating.
 
  • #4


A thread attaches a 2.74-g Ping-Pong ball to the bottom of a beaker. When the beaker is filled with water so that the ball is totally submerged, the tension in the thread is 6.87 mN. Determine the diameter of the ball.

The force pushing the ping pong ball up is the buoyant force of the water. Thus if the force pulling it down is equal, the tension is equal to the buoyant force. According to Archimedes principal, the buoyant force on a object immersed in fluid is equal to the weigh of the fluid displaced by that object. So the weight of the fluid displaced is 6.87 mn. Thus, the mass is 0.00687 N / 9.87 N = 0.000701 kg. Then, d = m*v. D of water is 1000 kg * m^3. Solving for volume, we get the volume as 7.0102 * 10^-7 m^3. Then we solve for volume with (x/2)^3 * pi * 4/3 = 7.0102 * 10^-7 m^3. I get x to = 0.011022 m. But this is not the answer; what am I doing wrong?
 
  • #5


tak08810 said:
The force pushing the ping pong ball up is the buoyant force of the water. Thus if the force pulling it down is equal, the tension is equal to the buoyant force.
You are forgetting about another force that acts on the ball.
 
  • #6


Redbelly98 said:
You are forgetting about another force that acts on the ball.

Ah thank you! So tension + gravity is the force going down and the buoyant force opposes it.
 

Related to Calculating Ball Diameter in a Beaker: Accounting for Tension and Buoyancy

1. What is the purpose of the ball in a beaker experiment?

The purpose of the ball in a beaker experiment is to measure the diameter of the ball using the volume displacement method. This experiment can also be used to understand how objects behave when placed in a liquid and the concept of buoyancy.

2. How is the diameter of the ball calculated in this experiment?

The diameter of the ball is calculated by measuring the volume of water displaced when the ball is submerged in the beaker. The volume of water is then divided by the height of the water level to obtain the diameter of the ball.

3. What factors can affect the accuracy of the diameter measurement in this experiment?

The accuracy of the diameter measurement can be affected by the precision of the measurement tools used, the shape and size of the ball, and the consistency of the water level in the beaker. It is important to ensure that all measurements are taken carefully and consistently to obtain accurate results.

4. Can this experiment be used to measure the diameter of irregularly shaped objects?

Yes, this experiment can be used to measure the diameter of irregularly shaped objects as long as the object can be fully submerged in the beaker and the volume of water displaced can be accurately measured.

5. How can this experiment be modified to measure the density of the ball?

This experiment can be modified by using a known mass of the ball and measuring the volume of water displaced. The density of the ball can then be calculated by dividing the mass by the volume. This method can also be used to compare the density of different objects.

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