Nenad said:
da_willem said:
Nenad said:if your trying to rack up posts, go ahead, but comments like that are not needed.
To calculate the velocity of a ball dropped from a moving helicopter, you will need to use the formula: v = √(2gh), where v is the velocity, g is the acceleration due to gravity (9.8 m/s²), and h is the height from which the ball is dropped.
The acceleration due to gravity is a constant value of 9.8 m/s² and represents the rate at which objects fall towards the earth due to the force of gravity.
Yes, air resistance can have an impact on the velocity of a ball dropped from a moving helicopter. However, for the purposes of this calculation, we assume that the ball is dropped in a vacuum, where there is no air resistance.
No, the velocity of a ball dropped from a moving helicopter cannot be negative. This is because the velocity is a vector quantity and represents both the magnitude and direction of the ball's motion. In this case, the velocity will always be positive, representing the downward motion of the ball.
The velocity of a ball dropped from a moving helicopter will increase as the height increases. This is because the ball has more potential energy when it is dropped from a higher height, which is then converted into kinetic energy as it falls. The velocity will continue to increase until it reaches its terminal velocity, which is the maximum velocity that the ball can reach due to air resistance.