- #1
Pete_L
- 27
- 1
Please see if you agree with how I am calculating the number of bricks required to reduce cooling off of my house overnight in the winter when I'm not there (sleeping) to feed logs into the stove.
The estimated weight of each log that I would normally be burning in my stove is 8.6 pounds. Assume that burning three of such logs overnight would prevent room temperature dropping from 75 deg. F to less than 60 deg. F. BTU of air dry wood equals approximately 5000. Three logs weigh in total 25.8 pounds, and thus produce total heat of 129,000 BTU.
The heat storage capacity of clay brick equals 0.21 BTU/pound-deg. F. Each brick weighs 4.6 pounds. The outside surface temperature of my stove is 600 deg. F. Room (air) temperature equals 75 deg. F. Thus,
(BTU/ 1 brick) = 0.21 X 4.6 pounds X (600 deg. - 75 deg.)
(BTU/ 1 brick) = 507
Then
Total required bricks = BTU of 3 logs/ BTU per brick
Total required bricks= 129000/ 507
Total required bricks = 254
Putting bricks along the sides, on top, and underneath the stove, I can fit about 100 bricks. Any more bricks would have other bricks between them and the stove. So my question is, if I place 100 bricks next to my stove, will this cause my house to be noticeably warmer in the morning, or would adding the bricks only slightly or not noticeably improve the room temperature in the morning?
The estimated weight of each log that I would normally be burning in my stove is 8.6 pounds. Assume that burning three of such logs overnight would prevent room temperature dropping from 75 deg. F to less than 60 deg. F. BTU of air dry wood equals approximately 5000. Three logs weigh in total 25.8 pounds, and thus produce total heat of 129,000 BTU.
The heat storage capacity of clay brick equals 0.21 BTU/pound-deg. F. Each brick weighs 4.6 pounds. The outside surface temperature of my stove is 600 deg. F. Room (air) temperature equals 75 deg. F. Thus,
(BTU/ 1 brick) = 0.21 X 4.6 pounds X (600 deg. - 75 deg.)
(BTU/ 1 brick) = 507
Then
Total required bricks = BTU of 3 logs/ BTU per brick
Total required bricks= 129000/ 507
Total required bricks = 254
Putting bricks along the sides, on top, and underneath the stove, I can fit about 100 bricks. Any more bricks would have other bricks between them and the stove. So my question is, if I place 100 bricks next to my stove, will this cause my house to be noticeably warmer in the morning, or would adding the bricks only slightly or not noticeably improve the room temperature in the morning?
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