- #1
il27
Homework Statement
A 1 kg parcel of dry air initially at a temperature of 15 Celsius (288 K) rises from ground level to its equilibrium height, which corresponds to a pressure of 750 hPa.
- What is the decrease in internal energy?
- What is the temperature of the air parcel at its equilibrium height?
- Assuming the parcel ascends at the dry adiabatic lapse rate, what is the height of the parcel at
Homework Equations
pV = mRT
dU/dT = cV
The Attempt at a Solution
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pV = mRT
R (dry air gas constant) = 287.056 J/kg*K
V = (mRT)/p
W = p∆V
W = -∆U
I am not sure if you are able to just plug the pressure (750 hpa), mass, temperature (288K), into the volume equation like that...