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Is that (2V)/(3C) or (2V/3)C ?PeachBanana said:
PeachBanana said:
PeachBanana said:
The formula for calculating charge with capacitors in series is Q = CV, where Q is the charge, C is the capacitance, and V is the voltage.
The equivalent capacitance for capacitors in series can be calculated by adding the reciprocals of each individual capacitance and then taking the reciprocal of the sum. In other words, 1/Ceq = 1/C1 + 1/C2 + ... + 1/Cn, where Ceq is the equivalent capacitance and C1, C2, etc. are the individual capacitances.
Yes, you can still calculate charge with capacitors in series even if the capacitors have different capacitance values. You will need to use the formula Q = CV, where C is the equivalent capacitance of the series circuit.
When capacitors are connected in series, the charge is divided between the capacitors. This means that the total charge will be less than the charge of any individual capacitor.
No, the charge on a capacitor in a series circuit cannot be negative. Capacitors store charge, so the charge on a capacitor will always be positive. If the calculated charge is negative, it means that the direction of the charge flow is opposite to the assumed direction.
