Calculating Collisions b/w N2 & O2 Molecules in Air

In summary, the conversation discusses the calculation of the average number of collisions per second between N_{2} and O_{2} molecules in air at a pressure of 1 X 10^5 and a temperature of 298K in a room with a volume of 100m^3. The solution involves finding the collision density, n, and then multiplying it by the volume to get the total number of collisions per second, N. There is a discrepancy between the author's calculated value for z and the value calculated by the person asking the question, which is attributed to the difference between calculating for the total collisions and the average number of collisions per second.
  • #1
jbowers9
89
1

Homework Statement


Beginning Calculations in Physical Chemistry
Barry R. Johnson & Stephen K. Scott

Calculate the average number of collisions per second between [tex]N_{2}[/tex] and [tex]O_{2}[/tex] molecules in air @ 298K and @ a pressure of 1 X [tex]10^5[/tex] in a room of volume V = 100[tex]m^3[/tex]. (Assume air has the composition 0.8[tex]N_{2}[/tex] & 0.2[tex]O_{2}[/tex])


Homework Equations



I follow the solution in the text, however, do you need the given volume to calculate z?
Can't it be calculated from z = [tex]\sigma[/tex] [tex]\overline{c}_{rel}[/tex] [tex]\eta[/tex] using p/kT?

The Attempt at a Solution

 
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  • #2
To get the collision density, n (collsions/ cm3-s), i.e. collisions per unit volume per second, one does not need the volume.

To get the total number of collisions/sec, N, in the room as called for in the problem, one needs N = nV, where V is the total volume.
 
  • #3
zzzzzz @ STP

Alrightee then. When I calculate z, I get an answer on the order of magnitude of [tex]10^9[/tex], and the book/authors get something on the order of [tex]10^38[/tex]. What is the descrepancy here?
 
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  • #4
  • #5
...will the real z @STP please stand up

If
z= [tex]\sigma_{{N_2}{O_2}}[/tex] [tex]\overline{c}_{rel}[/tex] [tex]\eta[/tex]

I can't figure out how to make the above read sigma c rel eta. I keep getting the error above even though the syntax is the same as below

and [tex]\sigma_{{N_2}{O_2}}[/tex] = 0.415[tex]nm^2[/tex]

[tex]\mu_{{N_2}{O_2}}[/tex] = 14.93gs/mol

gives [tex]\overline{c}_{rel}[/tex] = 650m/s

[tex]\eta_{{N_2}{O_2}}[/tex] = N/V =n[tex]N_a[/tex]/V = n[tex]N_a[/tex]p/nRT

and after canceling out Avogadro's number gives
[tex]\eta_{{N_2}{O_2}}[/tex] = p/kT

So z = (0.415 x [tex]10^{-18}[/tex])(650)(2.43 x [tex]10^{25}[/tex])
z= 6.55 x [tex]10^9[/tex] sec-1

The authors get z = 2.55 x [tex]10^{36}[/tex] sec-1

They calculate [tex]Z__{{N_2}{O_2}}[/tex] = [tex]\sigma_{{N_2}{O_2}}[/tex] [tex]\overline{c}_{rel}[/tex] [tex]N_a{^2}[/tex] [[tex]N_2[/tex]][[tex]O_2[/tex]] = 2.55 x [tex]10^{34}[/tex] sec-1 m-3
and multiply this value by the volume 100[tex]m^3[/tex] to get 2.55 x [tex]10^{36}[/tex] sec-1.

So where is my error?
 
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  • #6
z @ STP

I still can't figure out why there is such a large difference in the book's calculated value for z and my value. They do emphasize "total" collisions but this is because it is a mixture of gases.
 

FAQ: Calculating Collisions b/w N2 & O2 Molecules in Air

How do you calculate collisions between N2 and O2 molecules in air?

To calculate collisions between N2 and O2 molecules in air, you will need to use the kinetic theory of gases. This theory states that the average kinetic energy of gas molecules is proportional to their temperature. By knowing the temperature, pressure, and number of molecules in a given volume of air, you can calculate the average speed of the molecules and the frequency of collisions between N2 and O2 molecules.

What factors affect the frequency of collisions between N2 and O2 molecules in air?

The frequency of collisions between N2 and O2 molecules in air is affected by the temperature, pressure, and number of molecules in a given volume. A higher temperature and/or pressure will result in faster-moving molecules and a higher frequency of collisions. Additionally, an increase in the number of molecules in a given volume will also lead to more collisions between N2 and O2 molecules.

How can collision frequency be used to understand the properties of air?

Collision frequency can provide valuable information about the properties of air. By studying the frequency of collisions between N2 and O2 molecules, scientists can understand the behavior of gases under different conditions, such as temperature and pressure. This information can also be used to predict the behavior of air in various environments, such as in the Earth's atmosphere or in a laboratory setting.

What is the relationship between collision frequency and air pressure?

The relationship between collision frequency and air pressure is directly proportional. This means that as air pressure increases, the frequency of collisions between N2 and O2 molecules also increases. This is because an increase in pressure leads to a higher number of molecules in a given volume, resulting in more frequent collisions between the molecules.

How can calculating collisions between N2 and O2 molecules in air impact our understanding of atmospheric processes?

Calculating collisions between N2 and O2 molecules in air is important for understanding atmospheric processes. These collisions play a significant role in the exchange of energy and momentum within the atmosphere, which affects weather patterns and the distribution of gases in the Earth's atmosphere. By studying these collisions, scientists can gain a better understanding of atmospheric processes and how they may change in response to different factors, such as human activities and climate change.

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