Calculating Current from AL3 Atomic Mass

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In summary: This is known as the Earnshaw's theorem. In summary, the conversation discusses the relationship between atomic mass, charge, and current in aluminum (Al) ions. It also explores the possibility of containing and manipulating large amounts of charge in a confined space, and the effects of magnetic and static forces on charged objects.
  • #1
ctech4285
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ok i was thinking
AL3 atomic mass of 13, has 4.6e23 atom per kg
and 13.8e23 charge per kg
multiply that by 1.6e-19 and we have 2.2e5 coulomb
so moving this 1kg of AL3 past a point ones per second would equal a current of 22KA
 
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  • #2
Al has an atomic number of 13 which means that 13g of it has 6x10^23 atoms.
So a kilo has rather more atoms - about 1000/13 moles = 4.60x10^25 atoms

Getting all of them to Al 3+ would be tricky, but if you could then, yes you would have quite a lot of current flowing.
 
  • #3
ok 2.2e7 C per kg
so 2.2MA
i am wondering what would happen if you shoot a few grams out of a rifle at >300m/s

is there something i can buy that has + or- charge, like hosehold related?
 
  • #4
That's 4.6e25 atoms and 2.2e7 coulombs. Assuming you want this thing to be spherical, you are proposing stuffing these 2.2e7 coulombs into a sphere 8.9cm across. That means density of 5.94e10 coulombs/meter. I'm getting total energy of 2.5e14J. That's about 60kT. A small nuke worth of energy stored purely in electrostatic repulsion of Al3+ ions. Good luck containing that.

(Edit: Just for fun, you can also try computing electric field from it, and estimating the closest distance a living being can stand to this sphere without getting its electrons ripped out.)
 
  • #5
oops i didnt think of that..hmm...
whats the limit on charge density for normo self containing stuff?
 
  • #6
You could do it as a stream of ions in a vacuum, you would need one heck if a filamant to emit 1kg/s of Al3+ though!
 
  • #7
No, you couldn't. You need a confinement of some sort. Your only option is magnetic confinement, and then you end up energies with many magnitudes greater, and absolutely no materials that could actually sustain the fields.

Edit: The unbalanced charges you can actually store in normal materials are VERY small.
 
  • #8
K^2 said:
No, you couldn't. You need a confinement of some sort. Your only option is magnetic confinement, and then you end up energies with many mag
The OP only said they wanted to move a Kg of Al ions/second - they didn't say anything about doing it in one lump.
You would need a fairly chunky inductor for the ICP at one end and really-really-good grounging on the target at the other end!

Admittedly the current in a really big ion source is normally only a few 10mA - but that's just an engineering detail.
 
  • #9
NobodySpecial said:
Al has an atomic number of 13 which means that 13g of it has 6x10^23 atoms.
Umm, no, that is not what the atomic number means. It means that aluminum atoms have 13 protons. But they also have 14 neutrons (usually) which contribute significantly to the overall mass. Aluminum's atomic mass is 26.98 g/mole.
 
  • #10
NobodySpecial said:
The OP only said they wanted to move a Kg of Al ions/second - they didn't say anything about doing it in one lump.
Ah, I see. Yes, a high velocity beam with low density should be possible.
 
  • #11
Redbelly98 said:
Umm, no, that is not what the atomic number means. It means that aluminum atoms have 13 protons. But they also have 14 neutrons (usually) which contribute significantly to the overall mass. Aluminum's atomic mass is 26.98 g/mole.

ooops - sorry, lack of coffee.

los_alamos.png
 
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  • #12
how does PH relate to the static charge of an substance?

hey two charged objects moving on parallel paths wouth have an atractive magnetic force and a repuslive static force, is that right?
 
  • #13
ctech4285 said:
how does PH relate to the static charge of an substance?
It doesn't.
hey two charged objects moving on parallel paths wouth have an atractive magnetic force and a repuslive static force, is that right?
Yes, if they are both positive or both negative charges.
 
  • #14
And the attractive magnetic force can never exceed the repulsive force.
 

FAQ: Calculating Current from AL3 Atomic Mass

How do I calculate the current from AL3 atomic mass?

To calculate the current from AL3 atomic mass, you will need to use the formula I = Z × e × n, where I is the current, Z is the atomic number of AL3 (13), e is the elementary charge (1.602 × 10^-19 coulombs), and n is the number of AL3 atoms present.

What is the atomic mass of AL3?

The atomic mass of AL3 is the combined mass of all the protons, neutrons, and electrons in an AL3 atom. It is approximately 26.98 atomic mass units (amu) or 4.48 × 10^-26 kilograms.

How do I find the number of AL3 atoms present?

You can find the number of AL3 atoms present by dividing the given mass of AL3 by its atomic mass and then multiplying by Avogadro's number (6.022 × 10^23 atoms/mol). This will give you the number of AL3 atoms present in moles, which can then be converted to the desired unit.

Can I use the same formula to calculate current for other elements?

Yes, you can use the same formula (I = Z × e × n) to calculate current for any element. Just make sure to use the correct atomic number and atomic mass for the specific element you are calculating for.

What is the unit for current in this calculation?

The unit for current in this calculation is amperes (A), which is equivalent to coulombs per second (C/s). You can also use milliamperes (mA) or microamperes (μA) for smaller values of current.

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