- #1
farry1024
- 2
- 0
Question:
Assume that a 12V permanent magnet DC motor is to be used for moving the robot legs.
It has a stall current of 2 ampere and a no load speed of 3000 r.p.m.
Assumer that the friction at no load spped was so little that it can be neglected .
When the suply is at 11V, the motor is moving the legs at its rated speed of 2000 rom due to firction, what current would it draw?
I try to answer:
Vmax = 12V
Imax = 12A
ωmax = 3000 rpm <<<ω=omoega, i.e. rotational speed
V1 = 11V
I1 = unknown
ω1 = 2000 rpm
back e.m.f proportional to ω
ω1/ ωmax = back e.m.f 1 / back e.m.f max
and back e.m.f = V- Ir
ω1/ ωmax = [ V1 - I1 ( r ) ] / [ Vmax - I max (r)]
However, I find that I do not have the resistance, how can I calculate? thanks.
Assume that a 12V permanent magnet DC motor is to be used for moving the robot legs.
It has a stall current of 2 ampere and a no load speed of 3000 r.p.m.
Assumer that the friction at no load spped was so little that it can be neglected .
When the suply is at 11V, the motor is moving the legs at its rated speed of 2000 rom due to firction, what current would it draw?
I try to answer:
Vmax = 12V
Imax = 12A
ωmax = 3000 rpm <<<ω=omoega, i.e. rotational speed
V1 = 11V
I1 = unknown
ω1 = 2000 rpm
back e.m.f proportional to ω
ω1/ ωmax = back e.m.f 1 / back e.m.f max
and back e.m.f = V- Ir
ω1/ ωmax = [ V1 - I1 ( r ) ] / [ Vmax - I max (r)]
However, I find that I do not have the resistance, how can I calculate? thanks.