Calculating D field in a region between two charged surfaces

In summary, the D field in the region between the wire and cylinder must be calculated taking into account the piecewise solution, the presence of the dielectric material, and the direction of the electric field.
  • #1
MNightShamylan
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1. Question: There is a wire with charge, surrounded by a metal cylinder with opposite charge. There is a dielectric surrounding the wire, going out half way to the outer cylinder. Calculate the D field in the region between the cylinder and wire.

Homework Equations

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Gauss's law for displacement: integral D * da = Q(free enclosed)

The Attempt at a Solution

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It seems to me that there will be a piecewise solution, one for the gaussian surface inside the dielectric and one just outside it (but just inside the outer cylinder). If the surface area of the gaussian cylinder is 2pirL, then is the D field just Q/(2pirL)? It seems like this is just way too simple, and I feel like I'm missing something. I also don't see how this takes into account the gaussian surface inside the dielectric, which should be different. Any guidance would be appreciated/
 
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  • #2


Hello,

Thank you for your question. It appears that you are on the right track in using Gauss's law for displacement to solve this problem. However, there are a few things to consider in order to arrive at the correct solution.

Firstly, you are correct in thinking that there will be a piecewise solution, as the electric field and displacement field will behave differently in the different regions. In order to properly calculate the D field in the region between the cylinder and wire, you will need to consider the contribution from both the wire and the outer cylinder.

One important factor to consider is the presence of the dielectric material. This will affect the electric field and displacement field in the region between the wire and cylinder. In order to account for this, you will need to use the relative permittivity of the dielectric, denoted by ε_r, in your calculations. This factor will modify the D field in the region between the wire and cylinder, and will also affect the boundary conditions at the interface between the dielectric and the metal cylinder.

Another important point to consider is the direction of the D field. Remember that the D field is defined as the electric flux per unit area, and has units of C/m^2. Therefore, you will need to carefully consider the direction of the electric field and how it contributes to the D field in the region between the wire and cylinder.

Overall, your approach of using Gauss's law for displacement is a good starting point, but you will need to consider the effects of the dielectric and carefully consider the direction of the D field in order to arrive at the correct solution. I hope this helps guide you in the right direction. Good luck with your calculations!
 

Related to Calculating D field in a region between two charged surfaces

1. How do you calculate the D field in a region between two charged surfaces?

The D field, also known as the electric displacement field, can be calculated using the formula D = εE, where ε is the permittivity of the medium and E is the electric field. In the case of two charged surfaces, the D field can be calculated by summing the contributions from each surface.

2. What is the role of permittivity in calculating the D field?

Permittivity, represented by the symbol ε, is a measure of a material's ability to store electric charge. It plays a crucial role in calculating the D field as it relates the electric displacement to the electric field in a given medium.

3. Can the D field be negative in a region between two charged surfaces?

Yes, the D field can be negative in a region between two charged surfaces. This typically occurs when the electric field is directed opposite to the direction of the electric displacement, leading to a negative value for D.

4. How does the distance between the two charged surfaces affect the D field?

The distance between the two charged surfaces has a direct impact on the D field. As the distance increases, the electric field weakens, resulting in a decrease in the electric displacement and thus a lower D field value.

5. Are there any simplifying assumptions made when calculating the D field between two charged surfaces?

Yes, there are several simplifying assumptions that are often made when calculating the D field in this scenario. These include assuming that the surfaces are perfectly flat, that the charges are evenly distributed, and that there are no external electric fields present.

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