Calculating $\displaystyle \lim_{x\to 0}$ Complex Limit

In summary, we use L'Hospital's Rule multiple times to solve the limit $\displaystyle \lim_{x \to 0} \frac{x^2-\sin^2{x}}{\tan(3x^4)}$ and then use series expansion to find the final answer of $\frac{1}{9}$.
  • #1
Guest2
193
0
$\displaystyle \lim_{x \to 0} \frac{x^2-\sin^2{x}}{\tan(3x^4)}$

How do you calculate this one?

L'hopital gives me

$\displaystyle \lim_{x \to 0} \frac{2x\cos^2(3x^4)-\sin{2x}\cos^2(3x^4)}{12x^3}$
 
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  • #2
Guest said:
$\displaystyle \lim_{x \to 0} \frac{x^2-\sin^2{x}}{\tan(3x^4)}$

How do you calculate this one?

L'hopital gives me

$\displaystyle \lim_{x \to 0} \frac{2x\cos^2(3x^4)-\sin{2x}\cos^2(3x^4)}{12x^3}$

This is another $\displaystyle \begin{align*} \frac{0}{0} \end{align*}$ indeterminate form, so use L'Hospital's Rule again. If you keep getting indeterminate forms, keep using it...
 
  • #3
Prove It said:
This is another $\displaystyle \begin{align*} \frac{0}{0} \end{align*}$ indeterminate form, so use L'Hospital's Rule again. If you keep getting indeterminate forms, keep using it...
Yeah, but this time you have to use it like four times! :mad:

I got it solved by series expansion, though, so all is good. :)
 
  • #4
\(\displaystyle \begin{align*}\lim_{x\to0}\dfrac{x^2-\sin^2x}{\tan3x^4}&=\lim_{x\to0}
\dfrac{x^2-\sin^2x}{\sin3x^4}\cdot\lim_{x\to0}\cos3x^4 \\
&=\lim_{x\to0}\dfrac{2x-\sin2x}{12x^3\cos3x^4} \\
&=\lim_{x\to0}\dfrac{2x-\sin2x}{12x^3} \\
&=\lim_{x\to0}\dfrac{2-2\cos2x}{36x^2} \\
&=\lim_{x\to0}\dfrac{4\sin2x}{72x} \\
&=\lim_{x\to0}\dfrac{8\cos2x}{72} \\
&=\dfrac19\end{align*}\)
 
  • #5
greg1313 said:
\(\displaystyle \begin{align*}\lim_{x\to0}\dfrac{x^2-\sin^2x}{\tan3x^4}&=\lim_{x\to0}
\dfrac{x^2-\sin^2x}{\sin3x^4}\cdot\lim_{x\to0}\cos3x^4 \\
&=\lim_{x\to0}\dfrac{2x-\sin2x}{12x^3\cos3x^4} \\
&=\lim_{x\to0}\dfrac{2x-\sin2x}{12x^3} \\
&=\lim_{x\to0}\dfrac{2-2\cos2x}{36x^2} \\
&=\lim_{x\to0}\dfrac{4\sin2x}{72x} \\
&=\lim_{x\to0}\dfrac{8\cos2x}{72} \\
&=\dfrac19\end{align*}\)
Very nice, thank you.
 

FAQ: Calculating $\displaystyle \lim_{x\to 0}$ Complex Limit

1. What is a complex limit?

A complex limit is a concept in calculus that describes the behavior of a function as it approaches a specific point on the complex plane. It is typically denoted as $\displaystyle \lim_{z\to z_0} f(z)$, where $z_0$ is the point of interest and $f(z)$ is the function.

2. How do you calculate a complex limit?

To calculate a complex limit, you first need to determine if the function is continuous at the point of interest. If it is, then you can simply evaluate the function at the point to find the limit. If the function is not continuous, you will need to use algebraic manipulation and other techniques to simplify the expression and find the limit.

3. What is the difference between a complex limit and a real limit?

A complex limit involves functions that map real numbers to complex numbers, while a real limit involves functions that map real numbers to real numbers. Additionally, the concept of continuity is different for complex functions compared to real functions, which can affect the calculation of the limit.

4. What are some common techniques for evaluating complex limits?

Some common techniques for evaluating complex limits include algebraic manipulation, L'Hospital's rule, and the use of trigonometric identities. It is also helpful to have a good understanding of basic properties of complex numbers and their operations.

5. Can a complex limit have multiple values?

Yes, a complex limit can have multiple values. This can occur when the function has different values approaching the point of interest from different directions. In this case, the limit does not exist.

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