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Homework Statement
Electrons are accelerated from REST by a potential difference of 1.0 x 10^3 volts
They pass midway between two flat parallel plates 0.15m long and 0.030m apart. The electric field between the plates has a magnitude of 2.0 x 10^3 N/C. Determine how far an electron will be deflected (x) from it's original horizontal path by the time that it reaches the other end of the plates
I can't use most of the formulas because there is constant acceleration involved after it reaches the 0.35 m mark, thus I can't get a x nor a y and the acceleration is just in the X axis,
I'm really stuck!
can anybody please help me?
Homework Equations
e = 1.602 x 10^-19
m = 9.11 x 10^-11
k = 9.0 x 10^9 N M^2/C^2
ε = V/r
ε = Fe/q
Vf^2 = Vi^2 + 2ad
d = v2t - 1/2at^2
d = v1t - 1/2at^2
The Attempt at a Solution
First find the acceleration
F = ma
qε = ma
(1.602x10^-19)(2000) = 9.11 x 10^-31a
a = 3.52 x 10^14
next find the distance between starting position and the end of the plates
ε = V/r
2000 = 1000/r
r = 0.50
after that find the distance between starting position and the start of the plates
0.50 - 0.15 = 0.35m
next you find the final velocity (the second before the electron reach's the plates)
Vf^2 = Vi^2 + 2(3.52x10^24)(0.35)
vf = 1.6 x 10^7
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