Calculating Distance to Highway Patrol Car

  • Thread starter Naeem
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In summary, the driver in this situation was traveling at 85 mph when they saw a highway patrol car. They applied their brakes and decelerated at a constant rate of 4 mph/sec until they reached a speed of 65 mph. They then maintained a constant speed of 65 mph and passed the patrol car 15 seconds after applying the brakes. The patrol car was initially seen 10 seconds before passing it, and the distance between the two cars was approximately 650 meters.
  • #1
Naeem
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Q. Suppose you are driving on the interstate at 85 mph when you see a highway patrol car parked up ahead. You apply your brakes, decelerating at a constant rate of 4 mph/sec until you're reduced your speed to 65 mph. You then maintain a constant speed of 65 mph. You pass the patrol car 15 seconds after you initially applied the brakes and are relieved that he doesn't pull out after you. How far away was the highway patrol car when you first saw it?

Ans. Two different situations to this problem,

1st situation,

we can find the time, it took to reduce the speed from 85 mph to 65 mph

t = (85mph - 65mph) / 4 m/s2

t = 5 seconds. ( Note: It decelarates in the first phase @ the rate of

4mph / sec.)

2nd Situation

Thereafter, it continues, at a constant rate of 65 mph.

Use constatnt acc. equation.

x - xo = vot + 1/2 at^2

Will vo be 65mph

and t = 10 seconds

a = -4 mph /sec
-----------------------------------

For the first situation, knowing the time t = 5 seconds,

we need to use

x - xo = vot + 1/2 at^2 again

Here, what would vo be?

t would be 5 seconds for sure.

I think 'a' would be 4mph /sec

Am I right with the variables.

Please help anybody
 
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  • #2
Naeem said:
t = (85mph - 65mph) / 4 m/s2

t = 5 seconds. ( Note: It decelarates in the first phase @ the rate of

4mph / sec.)

Your answer looks good, but the units in your equation are off.


x - xo = vot + 1/2 at^2

Will vo be 65mph

and t = 10 seconds

a = -4 mph /sec

It's not clear what you're doing here. If you're solving for the distance the car travels while moving at a constant 65 mph, then "a" should be zero because the velocity is constant. Also, you need consistency with your units. If your times are going to be in seconds, then your velocities and accelerations should be meters (or miles) per second and meters (or miles) per second squared, not miles per hour and miles per hour per second.


For the first situation, knowing the time t = 5 seconds,

we need to use

x - xo = vot + 1/2 at^2 again

Here, what would vo be?

t would be 5 seconds for sure.

I think 'a' would be 4mph /sec

You're right that "t" would be 5 seconds, but "a" would be -4 mph/sec (be sure to convert this before putting it in) and v0 would be 85 mph.
 
  • #3
Got it !
 

FAQ: Calculating Distance to Highway Patrol Car

What is the Highway Patrol Problem?

The Highway Patrol Problem is a mathematical problem that involves finding the optimal number of patrol cars to assign to a highway in order to minimize response time to accidents and other emergencies.

Who came up with the Highway Patrol Problem?

The Highway Patrol Problem was first proposed by mathematician George Dantzig in 1954 as a way to model real-life patrolling scenarios.

What factors are considered in solving the Highway Patrol Problem?

The Highway Patrol Problem takes into account variables such as the length of the highway, the speed limit, the density of traffic, and the probability of accidents occurring.

How is the Highway Patrol Problem solved?

The Highway Patrol Problem can be solved using mathematical optimization techniques, such as linear programming or dynamic programming, to determine the most efficient allocation of patrol cars.

What are the potential benefits of solving the Highway Patrol Problem?

Solving the Highway Patrol Problem can lead to improved response times, reduced costs for highway patrol departments, and ultimately, increased safety for drivers on the highway.

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