- #1
josephpatricks
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Hi everybody. I haven't been in school a few years, and its second week into physics. I have what the book describes as the answer, and through several methods seem to come .5m away from the stated answer...I don't know if they just simplify it or not.
A dog runs back and forth between its two owners, who are walking toward one another. The dog starts running when the owners are 10m apart. If the dog runs with a speed of 3.0 m/s, and the owners walk with a speed of 1.3 m/s, how far has the dog traveled when the owners meet?
limit of change in x / change in t
From as far as I can see, the owners are covering 2.6 m/s on a 10ft gap, while the dog's traveling of 3.0m/s is being hastened as a limit from 10 to 0. I don't know how to use latex yet, but I took the limit of (3/2.6)x t, where t is 10. the answer I receive is 11.5m or 150/13, but the book puts the answer as 11m. I am frustrated by now and just want to bs some attribution to the dog not starting at the side of an owner, accounting for the .5 m, but I offer this to anyone who could give me a better explanation.
Homework Statement
A dog runs back and forth between its two owners, who are walking toward one another. The dog starts running when the owners are 10m apart. If the dog runs with a speed of 3.0 m/s, and the owners walk with a speed of 1.3 m/s, how far has the dog traveled when the owners meet?
Homework Equations
limit of change in x / change in t
The Attempt at a Solution
From as far as I can see, the owners are covering 2.6 m/s on a 10ft gap, while the dog's traveling of 3.0m/s is being hastened as a limit from 10 to 0. I don't know how to use latex yet, but I took the limit of (3/2.6)x t, where t is 10. the answer I receive is 11.5m or 150/13, but the book puts the answer as 11m. I am frustrated by now and just want to bs some attribution to the dog not starting at the side of an owner, accounting for the .5 m, but I offer this to anyone who could give me a better explanation.