Calculating Earth's Centripetal Force: Impact on Weight and Direction at 700mph

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The centripetal force acting on objects due to Earth's rotation is minimal, with a 1 kg weight experiencing a negligible change in weight when traveling at 700 mph. While the centripetal force can be calculated using the equation f=ma, its impact on a land racer's weight is not significant enough to be noticeable during such speeds. However, the effect can be more pronounced for high-speed aircraft like the Concorde, where passengers felt about 1% lighter flying east due to centripetal acceleration. Additionally, launching spaceships from closer to the equator can leverage this force for better efficiency. Overall, while centripetal force exists, its practical effects on weight at typical speeds are minimal.
ChrisAndre
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Considering Earth spins there is a centripetal force acting on us. How much force is acting on us? Say a 1Kg weight? Can someone give me an equation? Is it significant? I was wondering if land racer would be noticeably lighter or heavier if traveling in one direction or another at 700mph due to increased or decreased centripetal force.
 
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It can be significant depending on what you're trying to do. It's significant enough to try to launch spaceships from closer to the equator.

Concorde flew fast enough that you would feel about 1% lighter when flying east, due to centripetal acceleration...and another .6% due to height above the earth.
 
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

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