Calculating Electric Flux through a Cube with Given E-field in Region of Space

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In summary, the electric field in the given region is (8i + 2yj) N/C, and the magnitude of the electric flux through each face of the cube can be found using the integral \Phi = \int E \cdot dA = E\int dA = EA, where the dot product means only the perpendicular field is considered. The total flux is the sum of all six surfaces. To determine if there is any charge in the cube, Gauss's law may be used.
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OneTooMany
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1. The electric field in the region of space shown is given by E=(8i + 2yj) N/C where y is in m. A) What is the magnitude of the electric flux through each face of the cube. (3.0 M sides, 2.0m from yz axis)? B) Is there any charge in the cube?



2. E * da



3. To be honest I have absolutely no idea how to even begin. We did half of a kinda similar problem on the board on Friday. My professor is notorious for pulling this kind of stuff. There are a number of similar problems like this around but I can't seem to follow the logic. I am more concerned with understanding how to do the problem than what I get for a grade on this quiz. Thanks in advance for helping me with this
 
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OneTooMany said:
1. The electric field in the region of space shown is given by E=(8i + 2yj) N/C where y is in m. A) What is the magnitude of the electric flux through each face of the cube. (3.0 M sides, 2.0m from yz axis)? B) Is there any charge in the cube?

Part of your problem is no doubt that the question is not clear. What's a "yz axis"? Where is the cube actually located? What is its orientation?
 
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The flux can be found using [tex] \Phi = \int E \cdot dA [/tex]
The dot product inside the integral means you are looking only at the electric field passing perpendicularly though the surface. If the perpendicular field is constant over the surface the equation reduces to [tex] \Phi = \int E \cdot dA = E\int dA = EA[/tex] I would look at each of the six surfaces on the cube individually and find expression for the perpendicular field through it. If it is constant over that surface you can just use EA, but if it varies you will have to do the integral. The total flux will be the sum of all six surfaces. For part b look up Gauss's law.
 

FAQ: Calculating Electric Flux through a Cube with Given E-field in Region of Space

What is electric flux?

Electric flux is a measure of the amount of electric field passing through a given surface. It is represented by the symbol Φ and is measured in units of volts per meter squared (V/m²).

How is electric flux calculated?

Electric flux is calculated by multiplying the magnitude of the electric field by the area of the surface that the field is passing through and then taking the cosine of the angle between the electric field and the surface. This can be represented by the equation Φ = E * A * cos(θ).

What is the unit of electric flux?

The unit of electric flux is volts per meter squared (V/m²).

Can electric flux be negative?

Yes, electric flux can be negative. This occurs when the electric field is directed in the opposite direction of the surface normal, which results in a negative cosine value in the calculation of electric flux.

How is electric flux affected by the shape of the surface?

The shape of the surface does not affect the magnitude of electric flux. As long as the surface is perpendicular to the electric field, the same amount of flux will pass through regardless of its shape. However, the area of the surface will affect the total amount of flux passing through it, as shown in the equation Φ = E * A * cos(θ).

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