Calculating Electric Potential for a Point Above a Charged Conducting Slab

[012983]

Homework Statement

Let there be an infinite plate of positive charge density σ. Let there also be an uncharged conducting slab of a thickness h, placed above and parallel to the plate.

Without copying the question directly, I would like to know how one would calculate the electric potential for an arbitrary point C above the slab, at a distance c from the plate.

Homework Equations

V = kq/r, or 1/(4piε0)*(q/r)
V(for a charge distribution) = 1/(4piε0)*integral(dq/r)


If relevant, electric field between two conducting plates with surface charge densities +/- σ is E = σ/ε0.

The Attempt at a Solution

Apologies if anything below is incorrect.

Given the positive charge density of the plate, the side of the slab closest to the plate will have a positive surface charge density and the side farthest from the plate will have a negative surface charge density. I am at a loss as to how the slab affects the potential at point C.

In addition, I am not quite sure what the thickness of the slab has to do with this problem.

 

[jbsteele]

I am also unsure as to how the distance from the plate to point C would factor into the equation. My initial attempt at a solution is to use the electric field between two conducting plates formula, and then calculate the electric potential using the voltage equation given above. However, if this is incorrect, could anyone kindly explain how one would go about solving this problem? Thank you in advance!