Calculating Elevator Motor Work: 500 kg Lifted 50 m | Urgent Problem Solution

In summary, the work done by an elevator motor to lift a 500 kg elevator a height of 50 m is W = mg x 50m x cos0 = 0 J. The angle between the force and displacement is 90 degrees because the force is applied upwards and the elevator moves upwards, making the cosine of 0 degrees.
  • #1
dsptl
64
0
How much work does an elevator motor do to lift a 500 kg elevator a height of 50 m?

attempt: W = F.S.Cos90 = 0 J

but i think its not right... Please help some1?
 
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  • #2
dsptl said:
How much work does an elevator motor do to lift a 500 kg elevator a height of 50 m?

attempt: W = F.S.Cos90 = 0 J

but i think its not right... Please help some1?
Why is the angle between the force and the displacement 90o?
 
  • #3
is tht suppose to be 0 then?
 
  • #4
dsptl said:
is tht suppose to be 0 then?
Well, in which direction is the force applied? And in which direction is the elevator moving?
 
  • #5
upwards...

so is tht going to something like W = mg x 50m x cos0
 
  • #6
dsptl said:
upwards...

so is tht going to something like W = mg x 50m x cos0
Assuming that the elevator does not accelerate, that would be correct.
 

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