Calculating Empirical Formula | Antimony & Sulfur Reaction

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In summary, when 2.435g of Antinomy is heated with excess sulfur, a chemical reaction occurs. The excess sulfur is driven off, leaving only the compound. If 3.397g of the compound are prduced, the empirical formual of the compound is S8.
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extraordinarygirl
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When 2.435g of Antinomy is heated with excess sulfur, a chemical reaction occurs. The excess sulfur is driven off, leaving only the compound. If 3.397g of the compound are prduced, what is the empricial formula of the compound?

:frown: I am not even sure where to begin with this question because we were only given examples of how to do the empirical formuala when given the masses of each compound. Could someone please give me a hand of hwo to get started! Thank you
 
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  • #2
Antimony is an element, not a compound. It's trivial, but it may be important if you are asked this.

Anyway, the trick here is to convert all the weights (that was expressed in grams), including the mass of sulfur in the "compound", to their respective mole amounts. You'll understand this was easy part of the question when you are acutally making the "empirical" formula of said "compound"

good luck!
 
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  • #3
I am not understanding how I am supposed to covert the weight of sulfur in the compound if I don't know what the compound is. Is is Antimony + Sulfur? And if it is, how am I supposed to know what the charge of Antimony is?
 
  • #4
You are making it more complicated than it should. You don't have to "know" the compound to find the wieght of sulfur in the compound, you can do this in another very familiar way, which is called the law of conservation of mass and the empirical formula. The problem mentions these clues.

1. The antimony "in our box" reacts with "excess" sulfur.
2. The "excess" sulfur is then driven out.
3. Only the compound "in our box" remains.

Do you remember the law of conservation of mass?
 
  • #5
extraordinarygirl, to clarify what Umabel is saying, there's an assumption you need to make in solving this problem that should help a lot. Since it says antimony is reacted with excess sulfur, you can assume that ALL of the antimony is in your final product. Therefore, any additional mass in the final compound is due to the sulfur in the compound. That should help figure out how to calculate the number of moles of reactants and products.
 

FAQ: Calculating Empirical Formula | Antimony & Sulfur Reaction

What is "The Empirical Formula"?

The Empirical Formula is a chemical formula that shows the simplest ratio of elements in a compound. It is based on experimental data and is often used to determine the identity of an unknown compound.

How is "The Empirical Formula" different from "The Molecular Formula"?

The Empirical Formula shows the simplest ratio of elements in a compound, while the Molecular Formula shows the actual number of each element present in a molecule. The Molecular Formula is often a multiple of the Empirical Formula.

How is "The Empirical Formula" determined?

The Empirical Formula is determined through experiments such as combustion analysis or mass spectrometry. These methods measure the mass of each element present in a compound and allow us to calculate the simplest ratio of elements.

Can "The Empirical Formula" be the same as "The Molecular Formula"?

Yes, in some cases the Empirical Formula and the Molecular Formula can be the same. This happens when the compound has the simplest ratio of elements and cannot be reduced further.

Why is "The Empirical Formula" important in chemistry?

The Empirical Formula is important because it provides valuable information about the composition of a compound. It can help identify unknown substances and is used in stoichiometric calculations to determine reactant and product ratios in chemical reactions.

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