Calculating Energy Impact: Weight Required for 9 Joules at 1 Meter Height

[iqbaldadarkar]

1. How much weight is required to be dropped from 1 meter height so that on impact on ground will give 9 Joules of energy

 

[Pengwuino]

What are your thoughts on the matter?

 

[tomcue]

?[/b]

The amount of weight required to achieve 9 Joules of energy upon impact from a 1 meter height will depend on several factors such as the type of material used, the acceleration due to gravity, and the efficiency of the transfer of energy. In order to accurately calculate the weight needed, we would need to know the specific conditions and materials involved in the scenario.

However, in general, the formula for calculating potential energy is PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height from which the object is dropped. Using this formula, we can rearrange it to solve for the mass (m) required to achieve 9 Joules of energy:

m = 9J / (g * h)

Assuming a standard acceleration due to gravity of 9.8 m/s^2, we can estimate that a mass of approximately 0.92 kg (2.03 lbs) would be required to achieve 9 Joules of energy upon impact from a 1 meter height. However, as mentioned earlier, this calculation is based on several assumptions and may vary in real-world scenarios.