- #1
aquamarine08
- 23
- 0
[SOLVED] Power problem!
(a) How many joules of electrical energy are used by a 1650-W hair dryer in 10 min? (b) If the dryer is operated a total of 4.5 h during one month, how much will this contribute to the electrical bill if the billing rate is 12 cents/kWh?
P=[tex]\frac{w}{t}[/tex] --> w=Pt
(a) w=Pt -> (1650)(10)= 16500 J
I figured since the answer was supposed to be in Joules, I would use the equation w=Pt to figure out the amount but I ended up getting the wrong answer. The correct answer is 9.9 x [tex]10^{5}[/tex].
(b) Since I didn't get the right answer for (a) I knew my answer wouldn't be right here either. I don't really know how to solve this question either but I figured I should convert the 4.5 h into minutes so it matches the amount for part (a)..so I got 190 minutes, and that's pretty much it.
Please help, we didn't get any notes to refer to for this homework and it is our first day learning about Power.
Thanks so much.
Homework Statement
(a) How many joules of electrical energy are used by a 1650-W hair dryer in 10 min? (b) If the dryer is operated a total of 4.5 h during one month, how much will this contribute to the electrical bill if the billing rate is 12 cents/kWh?
Homework Equations
P=[tex]\frac{w}{t}[/tex] --> w=Pt
The Attempt at a Solution
(a) w=Pt -> (1650)(10)= 16500 J
I figured since the answer was supposed to be in Joules, I would use the equation w=Pt to figure out the amount but I ended up getting the wrong answer. The correct answer is 9.9 x [tex]10^{5}[/tex].
(b) Since I didn't get the right answer for (a) I knew my answer wouldn't be right here either. I don't really know how to solve this question either but I figured I should convert the 4.5 h into minutes so it matches the amount for part (a)..so I got 190 minutes, and that's pretty much it.
Please help, we didn't get any notes to refer to for this homework and it is our first day learning about Power.
Thanks so much.
Last edited: