- #1
tabsquare
- 5
- 0
hello I have a problem in calculating the equivalent impedance of a simple AC circuit, where the impedances are:
Z1 = 5+i20
Z2 = 5+i20
Z3 = 10-i2,5
Z4 = -i10
Z5 = 5
and I need to find:
Z_eq = Z3 // [(Z1 // Z4) + (Z2 // Z5)]
where the + indicates 2 components in serie and the // indicates 2 components in parallel.
My calculations always bring me to
Z_eq=6,25-i3,75
but my book says Z_eq=28,33.
Which is the correct eqv impedance?
Thank you
PS-I used the formula Za//Zb = (Za*Zb)/(Za+Zb)
to calculate equivalent impedances of two components in parallel, and the sum for components in serie.
Z1 = 5+i20
Z2 = 5+i20
Z3 = 10-i2,5
Z4 = -i10
Z5 = 5
and I need to find:
Z_eq = Z3 // [(Z1 // Z4) + (Z2 // Z5)]
where the + indicates 2 components in serie and the // indicates 2 components in parallel.
My calculations always bring me to
Z_eq=6,25-i3,75
but my book says Z_eq=28,33.
Which is the correct eqv impedance?
Thank you
PS-I used the formula Za//Zb = (Za*Zb)/(Za+Zb)
to calculate equivalent impedances of two components in parallel, and the sum for components in serie.