- #1
MattHorbacz
- 18
- 0
For my senior design project, my group is tasked with creating a wind turbine. At the moment, I am trying to figure out what approximate RPM the blades will rotate at so we can select an appropriate gear ratio and generator. Our advisor instructed us to use conservation of momentum on the turbine blade to get the force imparted by the airflow. Since we don't need an exact number, he told us to assume that the blade deflects the air by 90 degrees, and that velocity_in = velocity_out.
I figure that once you get the force acting in the y direction, you can plug into P=Fv=F(ωr) to get the radial velocity of the blade.
And I am not sure how to write "m dot" for mass flow rate, so i will use Ω instead.
Equations:
Vair=10 m/s
ρair=1.225 kg/m3
lengthblade (swept radius)=.457 m
max chord length=.089 m
Ablade=lengthblade*chord length (assuming blade to be a rectangle)
Cp=.45 ( the betz coefficient)
Attempt at Solution:
I figure that once you get the force acting in the y direction, you can plug into P=Fv=F(ωr) to get the radial velocity of the blade.
And I am not sure how to write "m dot" for mass flow rate, so i will use Ω instead.
Equations:
P=½ρAsweptV3Cp
P=Fv=F(ωr)
Ω=ρAbladeV
∑Fx=ΩinVin-Fx,blade=0
∑Fy=-ΩoutVout+Fy,blade=0
Known values:P=Fv=F(ωr)
Ω=ρAbladeV
∑Fx=ΩinVin-Fx,blade=0
∑Fy=-ΩoutVout+Fy,blade=0
Vair=10 m/s
ρair=1.225 kg/m3
lengthblade (swept radius)=.457 m
max chord length=.089 m
Ablade=lengthblade*chord length (assuming blade to be a rectangle)
Cp=.45 ( the betz coefficient)
Attempt at Solution:
Power is simple to calculate,
Power=.5*1.225kg/m*π*(.457m)2*(10 m/s)3*.45=181 W
Next, I solve the conservation of momentum equation in the y direction (the x direction doesn't tell me anything useful)
Fy,blade=ΩVout=ρAbladeV2=(1.225 kg/m3)*(.457 m)*(.089 m)*(10 m/s)^2=4.98 N
Now I plug that into P=Fv and find that v=36.35m/s. assuming the force acts in center of blade, ω=159 rad/s...I still convert to RPM even though this answer is obviously nowhere near correct...
(159 rad/s)(180 degrees/π rad)(1 rev/360 degrees)(60 s/min)=1518 RPM. Our advisor told us that the blade will have and RPM of around 60-120, which I feel is a bit low, but 1518 RPM is wayyyyy to high.I would very much appreciate any advice, whether it be where I messed up, or alternative ways of calculating RPM. Let me know if you would like any clarifications
Power=.5*1.225kg/m*π*(.457m)2*(10 m/s)3*.45=181 W
Next, I solve the conservation of momentum equation in the y direction (the x direction doesn't tell me anything useful)
Fy,blade=ΩVout=ρAbladeV2=(1.225 kg/m3)*(.457 m)*(.089 m)*(10 m/s)^2=4.98 N
Now I plug that into P=Fv and find that v=36.35m/s. assuming the force acts in center of blade, ω=159 rad/s...I still convert to RPM even though this answer is obviously nowhere near correct...
(159 rad/s)(180 degrees/π rad)(1 rev/360 degrees)(60 s/min)=1518 RPM. Our advisor told us that the blade will have and RPM of around 60-120, which I feel is a bit low, but 1518 RPM is wayyyyy to high.I would very much appreciate any advice, whether it be where I messed up, or alternative ways of calculating RPM. Let me know if you would like any clarifications