- #1
Menisto
- 18
- 0
A yo-yo of mass .3 Kg with a radius .03 m spins on an axel of radius .02 meters. It is dropped a distance .8 m, what is its final velocity?
I started:
mg -T=ma
mr(0)t = I(alpha)-->(alpha)= a/r
So:
mg - (Ia)/mr(0)^2 = ma
a = mg/ (m + I/(mr(0)^2)
I = 1/2 mR(1)^2
I checked over this numerous times and was unable to find my error, but I keep getting 2.06 for acceleration. The acceleration that would lead to the correct answer is 4.6 (m/s^2).
I started:
mg -T=ma
mr(0)t = I(alpha)-->(alpha)= a/r
So:
mg - (Ia)/mr(0)^2 = ma
a = mg/ (m + I/(mr(0)^2)
I = 1/2 mR(1)^2
I checked over this numerous times and was unable to find my error, but I keep getting 2.06 for acceleration. The acceleration that would lead to the correct answer is 4.6 (m/s^2).