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ND3G
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In many neighbourhoods, you might see parents pulling youngsters in a four-wheeled wagon. The child and the wagon have a combined mass of 50kg and the adult does 2.2 x10^3 J of work pulling the two 60m at a constant speed. The coefficient of friction for the surfaces in contact is 0.26
Determine the magnitude of the force applied by the parent
Given:
m = 50kg
W = 2200 J
d = 60m
u = 0.26
Required: Fapp
Analysis: Fapp = Fnet - Ff; Fnet = W/d; Ff = uFn; Fn = Fg; Fg = mg
Solution: Ff = (0.26)(50kg)(-9.8m/s^2) = -127.4 N
Fnet = 2200J / 60m = 36.7N
Fapp = 36.7N - (-127.4N) = 163.4N
Paraphrase: The Magnitude of the force applied by the parent is 163.4N.
Can someone kindly check this over for me and let me know if I have solved the question correctly? I haven't applied (cos) to the formula
W = F*cos*d but I wasn't sure how to solve for that part...
Determine the magnitude of the force applied by the parent
Given:
m = 50kg
W = 2200 J
d = 60m
u = 0.26
Required: Fapp
Analysis: Fapp = Fnet - Ff; Fnet = W/d; Ff = uFn; Fn = Fg; Fg = mg
Solution: Ff = (0.26)(50kg)(-9.8m/s^2) = -127.4 N
Fnet = 2200J / 60m = 36.7N
Fapp = 36.7N - (-127.4N) = 163.4N
Paraphrase: The Magnitude of the force applied by the parent is 163.4N.
Can someone kindly check this over for me and let me know if I have solved the question correctly? I haven't applied (cos) to the formula
W = F*cos*d but I wasn't sure how to solve for that part...