Calculating Force Between Two Conducting Spheres

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In summary, the conversation discusses two conducting spheres with charges of -4x10^-6 and 8x10^-6 C separated by a distance of 3.0cm. The force between them is calculated using the equation F=kq1q2/r^2, resulting in a value of -320N. If the spheres are touched together and separated again, the force between them is calculated using the new charges of 2x10^-6 C, resulting in a value of 40N. The direction of the force is attractive and repulsive respectively.
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Homework Statement



Two conducting spheres of the same size have charges q1=-4x10^-6
and q2 = 8x10^-6C,and their centers are separated by 3.0cm

a) what is the force between them?
b) what would be the force if the spheres were touched together and again separated by the same distance

Homework Equations



well we could use F=kq1q2/r^2


The Attempt at a Solution




for a) I plugged in 9x10^9 x -4x10^-6 x 8x10^-6 all divided by .09 which gives -3.2 but the answer is -320N.can someone explain my why?

for b) i don't know how it would start.
i tried doing several things. use the -320 as the separated force and
get the force of the one together and add them together.

something like that but i don't know how it gives 40N.
 
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  • #2
any help.
i still can';t figure this basic problem out
 
  • #3
Well... for a
F = kq1q2/r^2.. like you said. I plugged it in my calculator, and did
(9x10^9)(4x10^-6)(8x10^-6)/(.03)^2 and got 320 N... perhaps you did a calculation error, but that is how you set it up. I don't remember in class directly putting the negative into the equation, but perhaps the force is negative because you have opposite charges? (I'm not sure on direction)

As for b, if both spheres touch each other, afterwards they must have the same charge. If the spheres touch, then they will receive the same charge (2 x 10^-6 C). Therefore, just apply the new values of q to the equation.. and you should get something like
F = kq1q2/r^2 = (9x10^9)(2x10^-6)(2x10^-6)/(.03)^2 = 40 N

so a is a) 320 N (not sure about direction) and b is 40 N (also not sure of direction) ... do you see why?
 
  • #4
Oh.. and the reason the spheres each receive 2 x 10^-6 charge is because that is the amount of charge that is in the middle of both charges... notice how the first has -4 x 10^-6 and the second has 8 x 10^-6.. well the middle of -4 and 8 is 2, so that's how much each charge has! Just remember that when two spheres touch each other (of opposite charge), they must end up with the same charge.. so just take the middle of it!
 
  • #5
thanks for the great explanation.

the directions are just attractice and repulsive respectively.
 
  • #6
Oh okay ^^. You're welcome.. I hope it helped!
 

FAQ: Calculating Force Between Two Conducting Spheres

What is the purpose of studying two conducting spheres?

The study of two conducting spheres is important in understanding how electricity and electric fields behave in different situations. It can also provide insights into the properties of conductors and how they interact with each other.

How are the electric fields of two conducting spheres related?

The electric fields of two conducting spheres are related through the principle of superposition, meaning that the total electric field at any point is the sum of the individual electric fields produced by each sphere. This relationship also depends on the distance between the spheres and their respective charges.

Can two conducting spheres have the same charge?

Yes, two conducting spheres can have the same charge. However, this is only possible if they are both positively or negatively charged. If one sphere is positively charged and the other is negatively charged, they will naturally repel each other due to the interaction of their electric fields.

How do the charges on two conducting spheres affect each other?

The charges on two conducting spheres can affect each other through the interaction of their electric fields. If the spheres have opposite charges, they will exert attractive forces on each other. If they have the same charge, they will exert repulsive forces. Additionally, the charges can redistribute themselves due to induction, where the electric field of one sphere causes the charges on the other sphere to move.

How is the potential difference between two conducting spheres related to their charges and distance?

The potential difference, or voltage, between two conducting spheres is directly proportional to their charges and inversely proportional to the distance between them. In other words, as the charges on the spheres increase, the potential difference also increases, and as the distance between them increases, the potential difference decreases.

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