- #1
cc2hende
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Homework Statement
I have a plot whose vertical intercept is 0.00352 [Nm]
If the bearings are 2 [mm] from the center of the wheel,
then what is the force of friction?
Use three significant figures for your answer in Newtons.
Homework Equations
Torque= (Rotational Inertia)(Angular Acceleration)+ Torque due to friction
The Attempt at a Solution
Torque=0.00352Nm
Torque due to friction = (Rotational Inertia)(Angular Acceleration) - Torque
Tf= (I)*(A)-0.00352Nm
I don't even know how to attempt to solve for those other variables. Is this even the right equation to use?