Calculating Force P Needed to Lift 150kg Cylinder

In summary, the conversation discusses the problem of determining the smallest force P needed to lift a 150kg cylinder, taking into account the coefficients of static friction at different points (0.7 at A, 0.3 at B, and 0.4 at C). The speaker has tried different things to solve the problem, but is still unsure of how to proceed. They mention the use of two free body diagrams and equations to solve the problem, but are unable to provide them due to technical difficulties.
  • #1
Lancelot59
646
1
I've tried a whole manner of different things to try and solve this:

Prob.8-67.jpg


Determine the smallest force P needed to lift this 150kg cylinder.
Coefficients of static friction
At A: 0.7
At B: 0.3
At C: 0.4

I've tried different things and I'm lost on how to solve it.
 
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  • #2
Lancelot59 said:
I've tried a whole manner of different things to try and solve this:

Prob.8-67.jpg


Determine the smallest force P needed to lift this 150kg cylinder.
Coefficients of static friction
At A: 0.7
At B: 0.3
At C: 0.4

I've tried different things and I'm lost on how to solve it.

Could you please show us your two FBDs and what equations you have written so far?
 
  • #3
berkeman said:
Could you please show us your two FBDs and what equations you have written so far?

My scanner is giving me issues. It doesn't get along with Linux. I'll just describe them.

The drum has a normal and force of friction at point A At point B there is a normal that is at 80 degrees from the x axis, and different frictional force. It also has a weight force.

The wedge has the pushing force and the force of friction with respect to the ground on it. There is a force of friction at point B opposite to the direction on the drum, and a normal perpendicular to the top face. The problem didn't specify a mass for the wedge, so I decided to neglect it.

Normal Force At B:
FNB=150*9.8*sin(10)+Fp*sin(10)

Frictional Force At B:
FFB=0.3FNB

Normal Force At A:
I reasoned that the only thing pushing the cylinder into the wall would be it's own weight force pulling it down the wedge, and the horizontal component of the frictional force at point B

FNA= 150*9.8*sin(10)+FFBcos(10)

Frictional Force At A:
FFA=0.7FNA

Normal Force At C:
I think the only source would be the direct weight of the cylinder
FNC=150*9.8

Friction Between Wedge and Ground:
FFC=150*9.8*0.3
 

FAQ: Calculating Force P Needed to Lift 150kg Cylinder

How do you calculate the force needed to lift a 150kg cylinder?

The formula for calculating force (F) is mass (m) multiplied by acceleration due to gravity (g). So, to calculate the force needed to lift a 150kg cylinder, you would use the equation F = m x g. Plug in the values of 150kg for mass and 9.8m/s^2 for acceleration due to gravity, and you will get the force required in Newtons (N).

What is the standard unit of measurement for force?

The standard unit of measurement for force is Newtons (N). This unit is named after Sir Isaac Newton, a famous physicist who developed the laws of motion.

How do I convert the force needed to lift a 150kg cylinder into pounds?

To convert from Newtons to pounds, you would use the conversion factor 1N = 0.2248lbs. So, if the force calculated is 1470N, you would multiply it by 0.2248 to get 330.336lbs.

What other factors should be considered when calculating the force needed to lift a 150kg cylinder?

In addition to mass and acceleration due to gravity, the force needed to lift a cylinder may also depend on factors such as the surface area of the cylinder, the angle of lift, and the presence of any external forces acting on the cylinder.

How can I ensure that I am calculating the force accurately?

To ensure accurate calculation of force, it is important to use the proper units of measurement and double-check all values and calculations. It may also be helpful to consult with a colleague or refer to reliable resources for assistance.

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