- #1
nessan
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Homework Statement
How much force is required to throw a 1kg ball (from the ground) so that it stays 4 seconds in the air before it touches the ground again. Air resistance is insignificant.
Given data:
m=1kg, t=4s, a=-9,8m/s2 and ∆d=0 (because it hit the ground again)
Unknown data:
vi (initial), h (the height of the ball when it turns down) and F (the required force)
Homework Equations
First equation [tex]\ mgh=\frac{mv_i^2}{2}[/tex]
Second equation [tex]\Delta d=v_it+\frac{at^2}{2}[/tex]
Third equation [tex]\ W=Fd[/tex]
The Attempt at a Solution
By using the first equation i solved [tex]\ h=\frac{v_i^2}{2g}[/tex]
and then I solved vi using the second equation so [tex]\ v_i=\frac{\Delta d}{t}-\frac{at}{2}[/tex]
since ∆d is 0, [tex]\ v_i=-\frac{at}{2}[/tex]
to rewrite an equation for h without vi, I wrote vi as -at/2 so i got:
[tex]\ h=-\frac{at^2}{8}[/tex]
With the third equation mgh=Fd I solved F:
[tex]\ F=-\frac{mgat^2}{d}[/tex]
But d is the same as h so they cancel out and I get F=mg.
Can you please tell me what's wrong I'm doing and how to solve this problem.
Thanks in advance!