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kc0ldeah
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Homework Statement
http://imgur.com/BqIoe
There is a 50 meter bridge with two supports. The bridge has a mass of 80000kg. A truck of 30000 kg is 15m from one of the supports. What are the forces acting on the ends of the bridge?
Answers in back are F_a(support closer to truck): 598000 N and F_b: 480000 N
Homework Equations
torque = Force_perpendicular * distance
center of mass for uniform object is center of geometry
The Attempt at a Solution
Sum of Forces in y direction on bridge: = -80000g - 30000g + Fn A + Fn B = 0
Torque @ A = -15(30000) - 25(80000) + 50*Fn B = 0
Fn B = 490000
Torque @ A = 35(30000) + 25(80000) - 50*Fn A = 0
Fn A = 305000
What am I doing wrong? Any help is appreciated.