Calculating Forces on Two Charges Above a Conducting Sheet

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The discussion focuses on calculating the forces acting on two charges, +Q and -Q, positioned above a conducting sheet. The user attempted to solve the problem using the method of image charges, resulting in a complex expression for the force. They expressed difficulty in finding the modulus of the vector and writing it in components due to the complexity of their derived formula. Another participant confirmed that the user's answer appears to consist of vector components. The conversation highlights the challenges of applying image charge techniques in electrostatics.
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Homework Statement



Two charges +Q and -Q are a horizontal distance a apart and a vertical distance b above a large conducting sheet. Find the components of the forces acting on each charge.

Homework Equations





The Attempt at a Solution



Ok well I've tried to solve this using image charges (i.e. positing 2 imaginary charges below the plate) and have got an expression for F. My problem is that the expression is really horrible so i can't find the modulus of the vector bit and thus write it in components.. have i gone wrong?

my answer is F = kQ^2 times vector ( [1/a^2 - a/(a^2 + 4b^2)^3/2] , 0 , [2b/(a^2 + 4b^2)^3/2 - 1/4b^2] )

Thanks!
 
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Those look like vector components from where I'm sitting! :smile:
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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