Calculating Free Fall Time Using "g" Only

  • Thread starter Ahmedstein
  • Start date
In summary, the problem is to find the height of a cliff given the time it takes for an object to fall and the speed of light and free fall acceleration. The equation for displacement is y(t) = y0 - 1/2*g*t^2, and since the initial velocity is zero, it simplifies to y(t) = -1/2*g*t^2. Solving for y0, the height of the cliff, we get y0 = 1/2*g*t^2.
  • #1
Ahmedstein
19
0
Ok guys, I really need your help on this one. A free faling object from an unknown height. How can I get an equation to calculate the time that takes that object to reach the ground with only using "g" (free fall acceleration) and no other constant.

Pleease, if you love The Beatles, you'd help me. I tried everything and couldn't do it.
 
Physics news on Phys.org
  • #2
Ahmedstein said:
Ok guys, I really need your help on this one. A free faling object from an unknown height. How can I get an equation to calculate the time that takes that object to reach the ground with only using "g" (free fall acceleration) and no other constant.

Pleease, if you love The Beatles, you'd help me. I tried everything and couldn't do it.

...not just anybody? :biggrin:

Well, write down the equation of displacement and the equation of velocity of the object. Use a condition in every equation, and you can retrieve the time. (Hint 1: what is the velocity when it hits the ground? ; Hint 2: what is the displacement at the same time? )
 
  • #3
Set up Newton's 2.law with "m" signifying the (unknown) mass.
See what you can do with that m!
 
  • #4
@radou:The displacement when it hits the ground is the height from which the object was dropped, which I cannot use. and the velocity at that point is soo unknown.

@arildno: Mass does not matter in free fall

So the conclusion is: initial velocity is ZERO, accerleration is (-g) and t=?? .. maan, that's the most difficult problem, I've ever dealt with
 
  • #5
Set up Newton's 2.law! In symbols please!
 
  • #6
arildno said:
Set up Newton's 2.law! In symbols please!

F=m a :confused:
 
  • #7
arildno said:
Set up Newton's 2.law with "m" signifying the (unknown) mass.
See what you can do with that m!

dude, I'm not supposed to add new variables that are not mentioned in the problem.
 
  • #8
Ahmedstein said:
F=m a :confused:
Quite so!
And, what is F in this case?
 
  • #9
Ahmedstein said:
dude, I'm not supposed to add new variables that are not mentioned in the problem.
It doesn't say that explicitly, does it?
 
  • #10
arildno said:
Quite so!
And, what is F in this case?

the force of gravity?! :cry:
 
  • #11
Which in symbols can be written as??
 
  • #12
arildno said:
It doesn't say that explicitly, does it?

actually, it does. It is a computed homework system and if I use variables that are not in the problem it says "the answer doesn't not depend on that variable"

for example I tried that:
h is height or displacement
h= -0.5gt(squared)
t= square root of (2h/g)

I know it's a square root of a negative number, but I couldn't think of anything else. and it said "the correct answer doesn't depend on h" ... actually I am supposed to calculate the height. I just didn't tell you the whole problem.
 
  • #13
Ok, here it is. An object was dropped from the top of a cliff and the dropper heard the sound after (t) time. ok, and it's given in the question that speed of light is V, and free fall accerelation is a, and I should find the height of the cliff, so I figured out that I should use h= V * t, but I should subtract the time that took the object to reach the ground from the given (t), as the given t should equal (time that takes the object to hit the ground + time that takes sound to reach the top of the buiding to be heard) am I right?
 
  • #14
Ahmedstein said:
Ok, here it is. An object was dropped from the top of a cliff and the dropper heard the sound after (t) time. ok, and it's given in the question that speed of light is V, and free fall accerelation is a, and I should find the height of the cliff, so I figured out that I should use h= V * t, but I should subtract the time that took the object to reach the ground from the given (t), as the given t should equal (time that takes the object to hit the ground + time that takes sound to reach the top of the buiding to be heard) am I right?

Yes, sounds right.
 
  • #15
so it is h= v (t- ?) :(
 
  • #16
Ahmedstein said:
so it is h= v (t- ?) :(

Let's slow down. The equation for the y-displacement (which is the only direction of displacement, btw) is y(t) = y0 - 1/2*g*t^2, where y0 is the height of the cliff, you may call it h, if you want, doesn't really matter. So, you know the time, let's call it t1. So, we can write y(t1) = y0 - 1/2*g*t1^2. Now, what does y(t1) equal?
 
  • #17
shouldn't it be y(t) = V0 - 0.5 g t^2 , where V0 is the initial velocity, which in this case is equal to zero
 
  • #18
:rolleyes: :frown: :cry:
 
  • #19
Ahmedstein said:
shouldn't it be y(t) = V0 - 0.5 g t^2 , where V0 is the initial velocity, which in this case is equal to zero

In general, y(t) = y0 + v0*t -1/2*g*t^2. So, yes, the initial velocity v0 equals zero, and you're left with y(t) = y0 - 1/2*g*t^2.
 
Last edited:
  • #20
aaaahhhhhhh
 
  • #21
Does anyone have anything to say?
 
  • #22
Ahmedstein said:
Does anyone have anything to say?

Everything is said. :smile: As stated, y0 - 1/2*g*t^2 = 0, where y0 is your height, and t is the time you calculated.
 
  • #23
but dude, h is required in the problem, if I use this the answer is going to be:

h = V (t - square root of 2h/g)

that doesn't make any sense
 
  • #24
Ahmedstein said:
but dude, h is required in the problem, if I use this the answer is going to be:

h = V (t - square root of 2h/g)

that doesn't make any sense

What doesn't make any sense? h - 1/2*g*t^2 = 0 implies h = 1/2*g*t^2, and you know the time t, so just calculate h!
 
  • #25
Ahmedstein said:
Ok, here it is. An object was dropped from the top of a cliff and the dropper heard the sound after (t) time. ok, and it's given in the question that speed of light is V, and free fall accerelation is a, and I should find the height of the cliff, so I figured out that I should use h= V * t, but I should subtract the time that took the object to reach the ground from the given (t), as the given t should equal (time that takes the object to hit the ground + time that takes sound to reach the top of the buiding to be heard) am I right?

please read it again and tell me what that (t) represents

the (t) in the equation (h = 0.5 g t^2) is the objects time

it's not the same as the (t) in the problem
 
  • #26
You're right, I was a bit sloppy, I'm sorry. :smile: OK, let's start again. The first equation is h - 1/2*g*t1^2 = 0, where t1 is the time it took for the object to reach the ground. Now, you know that h = V*(t' - t1), where t' = (t) (the time until you heard the sound). So, you get the equation V*(t' - t1) = 1/2*g*t1^2, from which you can calculate t1.
 
Last edited:
  • #27
I think this problem is a bit advanced.Anyway, Thanks for the help everyone. You guys are great.
 

FAQ: Calculating Free Fall Time Using "g" Only

What is "g" and how is it related to free fall time?

"g" is the acceleration due to gravity on Earth, which is approximately 9.8 meters per second squared. It is related to free fall time because the time an object takes to fall freely is directly proportional to the value of "g".

Is "g" the same everywhere on Earth?

No, the value of "g" can vary slightly depending on factors such as altitude and latitude. However, for most practical purposes, it is considered to be constant at 9.8 meters per second squared.

How do I calculate free fall time using "g" only?

The formula for calculating free fall time using "g" only is t = √(2d/g), where t is the time in seconds, d is the distance in meters, and "g" is the acceleration due to gravity. Plug in the values for d and "g", and then take the square root of the result to find the free fall time.

Can I use this formula for objects with different masses?

Yes, this formula can be used for objects with different masses because the acceleration due to gravity is the same for all objects, regardless of their mass. However, this formula assumes that air resistance is negligible.

What are some real-world applications of calculating free fall time using "g" only?

Some real-world applications include calculating the time it takes for objects to fall from a certain height, determining the speed of objects in free fall, and predicting the trajectory of projectiles. This formula is also used in fields such as physics, engineering, and sports.

Back
Top