Calculating Frequency of Vibration for 0.3kg Mass Suspended from 200Nm Spring

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The discussion focuses on calculating the frequency of vibration for a 0.3kg mass suspended from a 200Nm spring. The solution involves using the formulas ω = √(k/m) and f = ω/2π. The calculated angular frequency (ω) is 25.82 radians per second, leading to a frequency (f) of 4.11 Hz. Participants confirm the calculations appear correct and express satisfaction with the solution. The discussion highlights the application of fundamental physics equations in solving vibration problems.
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Homework Statement


A mass of 0.3kg is suspended from a spring 200Nm. If the mass is displaced by 10mm from its equilibrium position and released, for the resulting vibration, calculate:

a. the frequency of vibration.


Homework Equations


ω = √ k/m
f = ω/2∏

The Attempt at a Solution


ω=√ 200/0.3 = 25.82 rads-1

so f = ω / 2∏

f = 25.82/2∏ = 4.11Hz

Does this seem to be correct? Any help would be appreciated.
 
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