Calculating Gadsden Diving Championship Judge Scorecard Distributions

On the other hand, there are two ways to get $10$ (namely $3+4+3$ and $2+5+3$), so it is not surprising that there are some solutions with $3,3,4$ and some with $2,2,6$.In summary, there are six possible ways to distribute the scorecards among the three judges, and no other ways are possible without swapping sets of $4$ scorecards between judges. This is because each judge must have one of the cards from $1$ to $3$, and there is only one way to get each of the scores $6$, $7$, $8$ and $9$. Also, the highest possible score is $
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In the Gadsden Diving Championships there is a panel of three judges. There are 12 scorecards with the numbers 1-12 on them, which are distributed so that each judge has four. After the diver has performed their routine, the judges each hold up a score card, and the diver's score is the sum of the three scorecards added together.

So, my question is:

What are all the different ways that the cards can be distributed among the judges, if all player scores from 6-29, except 10, were possible? Also, explain why ithere's no other way of distributing the scorecards. (other than swapping sets of 4 scorecards between judges)

Working Out:

I've already worked out some combinations, such as

View attachment 8172

Are there any others? Thanks!
 

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bio said:
In the Gadsden Diving Championships there is a panel of three judges. There are 12 scorecards with the numbers 1-12 on them, which are distributed so that each judge has four. After the diver has performed their routine, the judges each hold up a score card, and the diver's score is the sum of the three scorecards added together.

So, my question is:

What are all the different ways that the cards can be distributed among the judges, if all player scores from 6-29, except 10, were possible? Also, explain why ithere's no other way of distributing the scorecards. (other than swapping sets of 4 scorecards between judges)

Working Out:

I've already worked out some combinations, such as
Are there any others? Thanks!
Interesting problem! It probably helps if you are familiar with Kakuro puzzles.

Your first solution is wrong, because it does not give any way to show a score of $11$. Your other two solutions are correct, and I believe that there are also four other solutions.

Start by looking at how to achieve the small scores. There is only one way to get $6$, namely $1+2+3$. So each of the scorecards for $1$, $2$ and $3$ must be allocated to a separate judge. As in your solutions, let's agree that $1$ goes to Judge 1, $2$ to Judge 2, and $3$ to Judge 3.

Similarly, $7$ has to be $1+2+4$. So $4$ must go to Judge 3. There are two ways to express $8$, namely $1+3+4$ and $1+2+5$. But $3$ and $4$ are already both with the same judge, so the only available combination for $8$ is $1+2+5$, and therefore $5$ must also go to Judge 3.

Of the various combinations for $9$ (which any Kakuro player would know instantly), the only one available is $1+2+6$. So $6$ must go to Judge 3, whose collection is now complete.

There are now no ways to get the score $10$ without using two of the scorecards held by Judge 3. To get the score $11$, there is only one remaining possibility, namely $1+3+7$. So $7$ must go to Judge 2.

Now look at the highest scores. The only possibility for $29$ (given that Judge 3 has nothing higher than a $6$) is $6+11+12$. So $11$ and $12$ must go to different judges. That just leaves the scorecards $8$, $9$ and $10$. Any one of these can go to Judge 2, with the other two going to Judge 1. That leaves six possible solutions, as follows: $$\begin{array}{ccc}\text{Judge 1} & \text{Judge 2} & \text{Judge 3} \\ \hline 1,9,10,11 & 2,7,8,12 & 3,4,5,6 \\ 1,8,10,11 & 2,7,9,12 & 3,4,5,6 \\ 1,8,9,11 & 2,7,10,12 & 3,4,5,6 \\ 1,9,10,12 & 2,7,8,11 & 3,4,5,6 \\ 1,8,10,12 & 2,7,9,11 & 3,4,5,6 \\ 1,8,9,12 & 2,7,10,11 & 3,4,5,6 \end{array}$$

Notice that for every combination of scorecards from Judges 1 and 2, you obtain a sequence of four consecutive scores by adding either $3$, $4$, $5$ or $6$ from Judge 3. That cuts down considerably on the amount of work involved in checking that each of these solutions works.
 

FAQ: Calculating Gadsden Diving Championship Judge Scorecard Distributions

1. How is the Gadsden Diving Championship Judge Scorecard Distribution calculated?

The Gadsden Diving Championship Judge Scorecard Distribution is calculated by taking the average of the scores given by each judge for every dive in the competition.

2. What factors are considered when calculating the Gadsden Diving Championship Judge Scorecard Distribution?

The Gadsden Diving Championship Judge Scorecard Distribution takes into account the execution, difficulty, and overall impression of each dive, as well as any penalties or deductions given by the judges.

3. How do you ensure the accuracy and fairness of the Gadsden Diving Championship Judge Scorecard Distribution?

The Gadsden Diving Championship Judge Scorecard Distribution is calculated using a standardized scoring system and each judge undergoes extensive training to ensure consistency in their scoring. Additionally, the scorecards are reviewed and double-checked by multiple officials before being finalized.

4. Is the Gadsden Diving Championship Judge Scorecard Distribution the only factor in determining the winner of the competition?

No, the Gadsden Diving Championship Judge Scorecard Distribution is just one aspect of the overall scoring system. The final placement of each diver is determined by combining their scorecard distribution with other elements such as degree of difficulty and any penalties or deductions given by the judges.

5. Can the Gadsden Diving Championship Judge Scorecard Distribution be used to compare performances between different competitions or events?

No, the Gadsden Diving Championship Judge Scorecard Distribution is specific to the Gadsden Diving Championship and cannot be compared with scorecard distributions from other competitions as they may use different scoring systems and criteria.

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